Answer:
The probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.
Step-by-step explanation:
Denote the events as follows:
<em>X</em> = an elementary or secondary school teacher from a city is a female
<em>Y</em> = an elementary or secondary school teacher holds a second job
The information provided is:
P (X) = 0.66
P (Y) = 0.46
P (X ∩ Y) = 0.22
The addition rule of probability is:

Use this formula to compute the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job as follows:

Thus, the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.
Answer:
The probability of the combination {H, T and H} is 0.125.
Step-by-step explanation:
The sample space of flipping a quarter is:
S = {H and T}
The probability of both outcomes is same, i.e. P (H) = P (T) = 0.50.
It is provided that three quarters are flipped one at a time.
The outcomes of all the three quarters are independent of each other.
Compute the probability of the combination {H, T and H} as follows:


Thus, the probability of the combination {H, T and H} is 0.125.
The answer is 128......
if you expand them
-27 x -1024 x 216 divide by 216 x216
= -27 x -1024 divided by 216
-1024 x -1 divided by 8
= 1024 / 8
=128
Answer:

Step-by-step explanation:
We are given that


We have to find 
To find the value of
we will multiply f(x) by g(y)

Now,



Hence,
