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igor_vitrenko [27]
3 years ago
10

Solve the equation.4 2/5 + k= −3 2/11k=

Mathematics
1 answer:
Natali [406]3 years ago
6 0

Answer:

k = -3636

Step-by-step explanation:

you subtract 425 from both sides, it cancels out on the left and adds more to the right

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Raymoon sold an article at a loss of 5%. If he had sold it for 270 more, he would have gained 7% find the cost prize of article
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7 0
2 years ago
The sum of two-sevenths of a number and 3 is 9. Can you please write out into an equation>~
serg [7]

Answer:

2/7x +3=9

x=21

Step-by-step explanation:

Let the unknown be x.

Take 3 to the other side so: 2/7 multiplied by x= 6

Divide 6 by 2/7 to get the answer;

Therefore x=21

Sub back into equation to check answer.

4 0
3 years ago
Read 2 more answers
According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?
scoundrel [369]

we have

f(x) = 15x^{11} -6x^{8} + x^{3} - 4x + 3

we know that

<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms

x=\frac{p}{q}

p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.

So

in this problem

the constant term is equal to 3

and the first monomial is equal to 15x^{11} -----> coefficient is 15

So

possible values of p are 1, and\ 3

possible values of q are 1, 3, 5, and\ 15

therefore

<u>the answer is</u>

The all potential rational roots of f(x) are

(+/-)\frac{1}{15},(+/-)\frac{1}{5},(+/-)\frac{1}{3},(+/-)\frac{3}{5},(+/-)1,(+/-)3


3 0
3 years ago
Read 2 more answers
1 2 3 4 5 6 7 8 9 10
kirza4 [7]
Yes so i do need to doing the times and multipics then get a fraction then u will get tot eh answer
6 0
3 years ago
Determine which number has a greater magnitude."<br><br> 7 and -8
MariettaO [177]

Answer:

7

Step-by-step explanation:

-8 is a negative number for example if you have -8 and you wanna get it to 0 you add 8 you don't have to do that with 7 it's a "positive" number

3 0
3 years ago
Read 2 more answers
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