Question

Write the polar form of a complex number in standard form for %7D%29%20%2B%20isin%28%5Cfrac%7B%5Cpi%7D%7B2%7D%29%5D" id="TexFormula1" title="8[cos(\frac{\pi}{2}) + isin(\frac{\pi}{2})]" alt="8[cos(\frac{\pi}{2}) + isin(\frac{\pi}{2})]" align="absmiddle" class="latex-formula">

Answer 1

Answer:

Solution : 8i

Step-by-step explanation:

We can use the trivial identities cos(π / 2) = 0, and sin(π / 2) = 1 to solve this problem. Let's substitute,

$8\left[cos\left(\frac{\pi }{2}\right)+isin\left(\frac{\pi \:}{2}\right)\right]$ = $8\left(0+1i\right)$

And of course 1i = i, so we have the expression 8(0 + i ). Distributing the " 8, " 8( 0 ) = 0, and 8(i) = 8i, making the fourth answer the correct solution.