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Wittaler [7]
3 years ago
10

Given: PQ= TQ, UQ: QS

Mathematics
1 answer:
joja [24]3 years ago
3 0

Answer:

The required prove is shown below.

Step-by-step explanation:

Consider the provided statement.

The required figure is shown below:

 Statement                                             Reasons

PQ ≅ TQ; UQ ≅ QS                               Given

PQ = TQ, UQ = QS                     Definition of Congruence

PQ + QS = PS; TQ+QU = TU    Segment Addition Postulate

TQ + QS = PS                            Substitution  (PQ = TQ)

TQ + QS = TU                            Substitution  (QU = QS)

PS = TU                                    Transitive Property

Prove: PS ≅TU                          Definition of Congruence

Hence, the required prove is shown above.

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AB = 6 cm, AC = 12 cm, CD = ?

In triangle ABC, ∠CBA = 90°, therefore in triangle BCD ∠CBD = 90° also.

Since ∠BDC = 55°, ∠CBD = 90°, and there are 180 degrees in a triangle, we know ∠DCB = 180 - 55 - 90 = 35°

In order to find ∠BCA, use the law of sines:
 
sin(∠BCA)/BA = sin(∠CBA)/CA
sin(∠BCA)/6 cm = sin(90)/12 cm
sin(∠BCA) = 6*(1)/12 = 0.5
∠BCA = arcsin(0.5) = 30° or 150°
We know the sum of all angles in a triangle must be 180°, so we choose the value 30° for ∠BCA

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∠DCA = 30 + 35 = 65°

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