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Wittaler [7]
4 years ago
10

Given: PQ= TQ, UQ: QS

Mathematics
1 answer:
joja [24]4 years ago
3 0

Answer:

The required prove is shown below.

Step-by-step explanation:

Consider the provided statement.

The required figure is shown below:

 Statement                                             Reasons

PQ ≅ TQ; UQ ≅ QS                               Given

PQ = TQ, UQ = QS                     Definition of Congruence

PQ + QS = PS; TQ+QU = TU    Segment Addition Postulate

TQ + QS = PS                            Substitution  (PQ = TQ)

TQ + QS = TU                            Substitution  (QU = QS)

PS = TU                                    Transitive Property

Prove: PS ≅TU                          Definition of Congruence

Hence, the required prove is shown above.

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An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
How do I solve this Geometry problem?
tia_tia [17]

Answer:

you let other people do it also all in totle is 50,8 oe 3

Step-by-step explanation:

5 0
2 years ago
What is 3 over 2 divided by 1 over 4
laila [671]
That would be 6/1 which equals to 6 ~Eos
8 0
4 years ago
Translate and solve using proportions 6.5% of what number is $3.77
marshall27 [118]

Answer:

<u>The quantity is US$ 58, which 6.5% is US$ 3.77 </u>

Step-by-step explanation:

Number = x

6.5% of x = $ 3.77

6.5% = 0.065 = 65/1,000 = 13/200 (Dividing by 5)

3.77 = 3 + 77/100 (We can't simplify 77/100)

Thus,

13/200 * x = 3 77/100

13x/200 = 377/100

13x = 754 (Multiplying by 200 at both sides)

x = 754/13 (Dividing by 13 at both sides)

<u>x = 58</u>

7 0
4 years ago
Solve the problem 5x-8&lt;7x-4
kumpel [21]

Answer:

x>-2

Step-by-step explanation:

5x-7x<-4+8

-2x<4

x>-2

5 0
3 years ago
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