All categories

2 years ago

20 points

Mathematics

1 answer:

Elodia [21]2 years ago

3 0

<h2>Answer:</h2>

A one solution because it's x=1

<h3>Step By Step explanation:</h3>

this is the original problem

8x-3=3x+2

we want to have x by itself so. . .

we add three on both sides. it cancels -3. And 2+3=5

8x=3x+5

we subtract 3x on both sides so 8x-3x=5x and 3x cancels on the other side

5x=5

we divide by 5 on both sides to get x by itself

x=1

if it was 1=1 or x=x (the same on both side) it would've been infinite solutions. if the numbers didn't match like 4=6 it would've been no solution

You might be interested in

What is the volume of a cube if one side is 2x

Anarel [89]

Answer:

8x^3

you are welcome

5 0

2 years ago

Read 2 more answers

Which of the following equations describes the line shown

wariber [46]

(-4,4) (2,1)
gradient = (1-4)/(2--4) = -1/2
y = mx + c
y = -1/2x + c
Replace point (2,1) in the equation
1=-1/2(2) +c
c = 2
Equation : y = -1/2x + 2
y-2 = -1/2x
Answer is C.
Hope it helped!

6 0

2 years ago

How many students voted

Ivahew [28]

Answer:

Voted for what exactly? I could help you more if you had a more definitive question. Unfortunately, I cannot answer this for you.

5 0

2 years ago

The formula for the volume of a sphere is V = Ar3, where Vis the volume

nalin [4]

Answer: 4.7 inches

Step-by-step explanation:

435=4/3(3.14)r³

4 0

2 years ago

Solve this x²+8/10 -x = 10/2

AysviL [449]

$x^2+\frac{8}{10}-x=\frac{10}{2}\\
x^2-x+\frac{8}{10}-\frac{10}{2}=0\\
x^2-x+\frac{8}{10}-\frac{50}{10}=0\\
x^2-x-\frac{42}{10}=0\\
x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\
(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\
(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\
(x-\frac{1}{2})^2=\frac{89}{20}\\
x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\
x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\


$
$x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\
x=\frac{1}{2}+\frac{\sqrt{445}}{10} \vee x=\frac{1}{2}-\frac{\sqrt{445}}{10}}\\
x=\frac{5+\sqrt{445}}{10} \vee x=\frac{5-\sqrt{445}}{10}}\\$

7 0

2 years ago