All categories

3 years ago

20 points

Mathematics

1 answer:

Elodia [21]3 years ago

3 0

<h2>Answer:</h2>

A one solution because it's x=1

<h3>Step By Step explanation:</h3>

this is the original problem

8x-3=3x+2

we want to have x by itself so. . .

we add three on both sides. it cancels -3. And 2+3=5

8x=3x+5

we subtract 3x on both sides so 8x-3x=5x and 3x cancels on the other side

5x=5

we divide by 5 on both sides to get x by itself

x=1

if it was 1=1 or x=x (the same on both side) it would've been infinite solutions. if the numbers didn't match like 4=6 it would've been no solution

You might be interested in

If 40% of a number is 56 what was the original number

svp [43]

Percent is pars out of 100
40%=40/100=4/10=0.4
'of' means multiply
0.4 times something=56
divide both sides by 0.4
something=140

th enumber is 140

5 0

3 years ago

What are the values for the coefficients and constant term of 2 + 3x² - 5x?<br> a=<br> B=<br> C=

Aleks [24]

Answer:

a=3

b=-5

c=2

Step-by-step explanation:

Because first arrange them in decreasing order by their variables powers like this 3x²-5x+2 after that take the the coefficients

5 0

2 years ago

Find the center and radius of the circle whose equation is x 2 + y 2 + 10x − 1

Margaret [11]

we conclude that the center of the circle is the point (-5, 0).

<h3>How to find the center of the circle equation?</h3>

The equation of a circle with a center (a, b) and a radius R is given by:

$(x - a)^2 + (y - b)^2 = R^2$

Here we are given the equation:

$x^2 + y^2 + 10x - 1 = 0$

Completing squares, we get:

$x^2 + 10x + y^2 = 1$

Now we can add and subtract 25 to get:

$x^2 + 10x + 25 - 25 + y^2 = 1\\\\(x + 5)^2 -25 + y^2 = 1\\\\(x + 5)^2 + (y - 0)^2 = 26$

Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).

If you want to learn more about circles:

brainly.com/question/1559324

#SPJ1

3 0

2 years ago

Aya = a1 + (n - 1)d

Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

Step-by-step explanation:

Given

a₁ = -33

d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

substituting a₁ = -33 and d = 4 in the nth term of the sequence

$a_n=-33+\left(n-1\right)4$

$\:a_n=-33+4n-4$

$a_n=4n-37$

Thus, the nth term of the sequence is:

$a_n=4n-37$

now substituting n = 26 in the nth term to determine the 26th term of the sequence

$a_n=4n-37$

$a_{26}=4\left(26\right)-37$

$a_{26}=104-37$

$a_{26}=67$

Therefore, the 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

7 0

2 years ago

Please help with the precalc question above...

Sonja [21]

Answer:

the last choice

Step-by-step explanation:

two functions are said to be inverse when they are symmetric about the line y=x

4 0

3 years ago