Answer:
a) h(x; 7, 5, 12) = (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)
b) 2.92
Step-by-step explanation:
a)
Here
Number of interviewees = N = 12
Number of job openings = M = 5
Interviews schedules for the first day = n = 7
N − M = 12 - 5 = 7
Using hypergeometric distribution:
Let X be the no. top four candidates interviewed on first day.
The probability mass function of X:
P(X = x) = 
/ 
It can be written as:
h(x; n, M, N) = /
= (5Cx) (7C7-x) / (12C7)
= (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)
h(x; 7, 5, 12) = (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)
b)
The expectation is: E(X) = np
E(X) = n * M/N
= 7 * 5/12
= 7 * 0.41667
= 2.9167
15 - 4t = 3
-15 -15
-4t = -12
-4t/-4 = -12/-4
t = 3
26) Answer is choice A: y = -3
This is the horizontal line that cuts the figure into two congruent pieces.
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27) Answer is choice A: AB = 24 and DE = 12
CA/DF = 12/6 = 2
CB/FE = 20/10 = 2
The ratio of the larger to smaller corresponding sides is 2:1 or just 2
So AB needs to be twice as long as DE
That only happens with choice A
(3x+4)+(5x2-1)+(2x+6)
remove unnecessary parenthesis
3x+4+(5x2-1)+(2x+6)
3x+4+(10-1)+2x+6
subtract the numbers
3x+4+9+2x+6
collect the like terms
5x+4+4+9+6
5x+19
Answer: it’s a
Step-by-step explanation:
