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oksano4ka [1.4K]
3 years ago
7

A rectangle is 64 cm long 40 cm wide find is area and perimeter​

Mathematics
1 answer:
kow [346]3 years ago
7 0

Answer:

Assuming the length to be x and the width to be y.

Since the area is 64cm, hence

x*y = 64 (equation 1)

Since the perimeter is 40cm, hence

x + x + y + y = 40

2x + 2y = 40

2(x + y) = 2(20)

x + y = 20 (equation 2)

Hence by using simultaneous equation,

x = 20 - y (equation 3)

Substituting equation 3 into equation 1, we get

(20-y)*y=64

20y-y^2=64

Tidying up the equation,

y^2 - 20y + 64 = 0

By using factorisation,

(y-16)(y-4)=0

y=16 or y=4

By substituting y=16 into equation 1,

x*16=64

x = 4

By substituting y = 4 into equation 1,

x*4=64

x=16

Therefore,

The length is 4 cm while the width is 16 cm.

OR

The length is 16 cm while the width is 4cm.

Hope this helps!!

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Answer:

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4 years ago
In a die game, you roll a standard 6-sided die twice. If the second number rolled is the same as the first number rolled, you wi
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Answer:

You can expect to make $250.

Step-by-step explanation:

Possible outcomes:

For the pair of dice:

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

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(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

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So 36 total outcomes.

Probability of the second number rolled being the same as the first number rolled:

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Out of 36, thus:

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Expected value of 1 game:

1/6 probability of earning $25.

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5 0
3 years ago
Hi, just wanted to double check your hat this is the right answer or not! If not can you please explain to me in comments? Thank
Elina [12.6K]

Yea that can be a good equation. I had this question last year and my teacher said it was ok.

But it can be wrong, I don't really know. Cuz we don't go to the same school.

6 0
3 years ago
Read 2 more answers
Suppose the function of h is defined, for all real numbers as follows: (f) x = -3 if x is <) 3 if x is =0 -2 if x is > 0
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Answer:

See explanation

Step-by-step explanation:

The question is not properly presented; I will answer this with the following similar question.

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Required

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This implies that: x = -5

-5 \ne 2

So, we make use of:

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h(-5) = -\frac{25}{3} + 4

Take LCM

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<u>Calculating h(2)</u>

This implies that: x = 2

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So, we make use of:

h(x) = -4

Substitute 2 for x

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<em>Use the above explanation to answer your question</em>

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