Answer:
2, 5, 14, 41, 122
Step-by-step explanation:
Using the recursive rule with a₁ = 2
a₂ = 3a₁ - 1 = 3(2) - 1 = 6 - 1 = 5
a₃ = 3a₂ - 1 = 3(5) - 1 = 15 - 1 = 14
a₄ = 3a₃ - 1 = 3(14) - 1 = 42 - 1 = 41
a₅ = 3a₄ - 1 = 3(41) - 1 = 123 - 1 = 122
The first 5 terms are 2, 5, 14, 41, 122
Answer:
Step-by-step explanation:
We have the equations
4x + 3y = 18 where x = the side of the square and y = the side of the triangle
For the areas:
A = x^2 + √3y/2* y/2
A = x^2 + √3y^2/4
From the first equation x = (18 - 3y)/4
So substituting in the area equation:
A = [ (18 - 3y)/4]^2 + √3y^2/4
A = (18 - 3y)^2 / 16 + √3y^2/4
Now for maximum / minimum area the derivative = 0 so we have
A' = 1/16 * 2(18 - 3y) * -3 + 1/4 * 2√3 y = 0
-3/8 (18 - 3y) + √3 y /2 = 0
-27/4 + 9y/8 + √3y /2 = 0
-54 + 9y + 4√3y = 0
y = 54 / 15.93
= 3.39 metres
So x = (18-3(3.39) / 4 = 1.96.
This is a minimum value for x.
So the total length of wire the square for minimum total area is 4 * 1.96
= 7.84 m
There is no maximum area as the equation for the total area is a quadratic with a positive leading coefficient.
-343,000 x 1/3 = -114,333.333333333219
Step-by-step explanation:
Hope it helps you in your learning process.
We are given the equation:
F = 2.25+0.2(m-1)
where:
F is the fare
m is the number of miles.
In question 7, we are given that the fare (F) is equal to $6.05 and we need to get the number of miles. To do so, we will simply substitute with the fare in the given equation and solve for the number of miles (m) as follows:
F = 2.25 + 0.2(m-1)
6.05 = 2.25 + 0.2(m-1)
6.05-2.25 = 0.2(m-1)
3.8 = 0.2(m-1)
3.8/0.2 = m-1
19 = m-1
m = 19+1
m = 20 miles
Number 8 is exactly the same, but we will substitute F=7.65 and again solve for m
