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Sedaia [141]
3 years ago
9

A company has 7 male and 9 female employees, and needs to nominate 2 men and 2 women for the company bowling team. How many diff

erent teams can be formed?
Please help :)
Mathematics
1 answer:
lys-0071 [83]3 years ago
5 0

Answer:

The team can be formed in 756 different ways

Step-by-step explanation:

This is a combination problem since we are to select a set of people from a group. Combination has to do with selection.

for example, if r number of object is to be selected from a pool of n objects, this can be done in nCr number of ways.

nCr = \frac{n!}{(n-r)!r!}

Now If A company has 7 male and 9 female employees, and needs to nominate 2 men and 2 women for the company bowling team, then this can be done in the following way;

7C2 * 9C2

7C2 = \frac{7!}{5!2!} \\= \frac{7*6*5!}{5!*2} \\= 7*3\\= 21ways\\\\similarly;\\\\9C2 = \frac{9!}{7!2!}\\9C2= \frac{9*8*7!}{7!*2} \\9C2 = 9*4\\9C2 = 36

7C2 * 9C2 = 21*36

= 756

The team can be formed in 756 different ways

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Ugo [173]

Answer:

divide this amount ($88.26875) by the number of people

Step-by-step explanation:

6.75% of $72.50 is 4.89375

15% of $72.50 is 10.875

72.50 + 4.89375 + 10.875 = 88.26875

divide this amount (88.26875) by the number of people

7 0
3 years ago
A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri
GuDViN [60]

Answer:

1.\frac{dy}{dt}=ky

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

\frac{dy}{dt}=Number of bacteria per unit time

\frac{dy}{dt}\proportional y

\frac{dy}{dt}=ky

Where k=Proportionality constant

2.\frac{dy}{y}=kdt,y'(0)=100

Integrating on both sides then, we get

lny=kt+C

We have y(0)=200

Substitute the values then , we get

ln 200=k(0)+C

C=ln 200

Substitute the value of C then we get

ln y=kt+ln 200

ln y-ln200=kt

ln\frac{y}{200}=kt

\frac{y}{200}=e^{kt}

y=200e^{kt}

Differentiate w.r.t

y'=200ke^{kt}

Substitute the given condition then, we get

100=200ke^{0}=200 \;because \;e^0=1

k=\frac{100}{200}=\frac{1}{2}

y=200e^{\frac{t}{2}}

Substitute t=2

Then, we get y=200e^{\frac{2}{2}}=200e

y=200(2.718)=543.6=543.6

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0
3 years ago
Biruk wants to buy a book for $15.25 and a book for $4.85. He wants to pay with one $20 bill. Use estimation to decide if this i
ycow [4]
First round 15.25 to 15.30 and round 4.85 to 4.90 and then add you get 21.20  no it is not reasonable and you round to the decimal ones
8 0
3 years ago
Read 2 more answers
You put $500 in the bank, where it ears 1.5% simple interest every year. How long until your money will triple?
zzz [600]

Answer:

133.33 years

Step-by-step explanation:

Given that:

Principal = $500

Interest rate (r) = 1.5% = 0.015

Triple amount of principal = $500 * 3 = $1500 = final amount (A)

Number of years (t) =?

Using the relation :

A = P(1 + rt)

1500 = 500(1 + 0.015t)

1500 / 500 = 1 + 0.015t

3 = 1 + 0.015t

3 - 1= 0.015t

2 = 0.015t

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133.333 = t

133.33 years

3 0
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