Answer:
int k;
double d;
char s[10];
cin >> k >> d >> s;
cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s;
Explanation
First Step (declare K, d, s) so they can store a integer
int k;
double d;
char s[10];
Second Step (read in an integer, a real number and a small word)
cin >> k >> d >> s;
Third Step ( print them out )
cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s;
Answer:
The program in C++ is as follows:
#include <iostream>
using namespace std;
void display(int array_test [], int n){
for(int i = 0; i<n;i++){
cout<<array_test[i]<<" "; }
}
int main(){
int n;
cin>>n;
int array_test[n];
for(int i = 0; i<n;i++){
cin>>array_test[i];
}
display(array_test,n);
return 0;
}
Explanation:
This defines the display function
void display(int array_test [], int n){
This iterates through the array
for(int i = 0; i<n;i++){
This prints each element of the array
cout<<array_test[i]<<" "; }
}
The main begins here
int main(){
This declares n as integer; n represents the length of the array
int n;
This gets input for n
cin>>n;
This declares the array
int array_test[n];
The following iteration gets input for the array
for(int i = 0; i<n;i++){
cin>>array_test[i];
}
This calls the display function to display the elements of the array
display(array_test,n);
return 0;
}
Answer:
1. When an object of the class is passed (to a function) by value as an argument.
2. When an object is constructed based on another object of the same class.
3. When compiler generates a temporary object.
Explanation:
