Answer:
The number of palindromes is
when n is even and
when n is odd
Step-by-step explanation:
From the question we are told that
The length of the string is 
Generally palindrome is evaluated by considering the first part of a string
When the the length of the string is an even number then
it means that the first part of the string is 
Hence the number of bit strings of length n that are palindromes is evaluated as

But When the the length of the string is an odd number then
it means that the first part of the string is 
Hence the number of bit strings of length n that are palindromes is evaluated as

Generally each bit could be either 0 or 1
Hence the number of palindromes is
when n is even and
when n is odd
If you draw out lmno as a parallelogram, then lo is always going to be opposite of nm which means they are equal to each other. nm = ol or x+11=2x+4 or 7 = x, then nm = ol = 18...
Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
<h3>
How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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Answer:
Area is 70ft
Step-by-step explanation:
Area of a triangle is A=b × h/ 2 or A=1/2×bh
Let height equal h & base equal b
So,
h=14
b=10
Solve,
A=1/2×14×10
A=1/2×140
A=70
Therefore, the area is 70 feet