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ella [17]
3 years ago
8

Timothy is sorting his building blocks into 8 bins. Each bin can hold 286 blocks. He has already put 74 blocks in the bins. How

many more blocks does Timothy need to sort?
Mathematics
1 answer:
Len [333]3 years ago
7 0

Answer: 2214 blocks

Step-by-step explanation:

From the question, we are told that Timothy is sorting his building blocks into 8 bins and that each bin can hold 286 blocks. Therefore, the total blocks that the bins would hold would be:

= 286 × 8

= 2288 blocks.

We are further told that he has already put 74 blocks in the bins. The number of remaining blocks that Timothy need to sort would be:

= 2288 - 74

= 2214 blocks

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Priya rode her bike 1250 feet. If her bike wheel has a diameter of 2.5 feet, how many times did her wheel make a full rotation?
Alex17521 [72]

Answer:

  • 159 times

Step-by-step explanation:

<h3>Given</h3>
  • d = 2.5 ft
  • Distance = 1250 ft
<h3>To find</h3>
  • Number of rotations
<h3>Solution</h3>

<u>Circumference of the wheel is the one full rotation:</u>

  • C = πd = 3.14*2.5 = 7.85 ft

<u>Number rotations:</u>

  • 1250/7.85 = 159.2

<u>Correct option is</u> 159 times

5 0
3 years ago
Simplify: 3 . 3^2 + 8 ÷ 2 - (4 + 3) A: 32 B: 24 C: 23 D: 30
yaroslaw [1]

Answer:

its none of these answers ;-;

Step-by-step explanation:

3^2 + 8 ÷ 2 - (4 + 3)

we do what's in parentheses first. (pemdas)

so now we have, 3^2 + 8 ÷ 2 - 7

next exponents, 3^2=9

9 + 8 ÷ 2 - 7

next division, 8÷2=4

9 + 4 - 7

next addition, 9+4=13

13-7

finally subtraction, 13-7=6

final answer: 6

7 0
4 years ago
Can someone please help and show work
Bad White [126]
Answer:$8.60
I put the work into the picture. Hope this helps!

7 0
3 years ago
Explain why if a runner completes a 6.26.2​-mi race in 3434 ​min, then he must have been running at exactly 1010 ​mi/hr at least
iren [92.7K]

Answer:

All speed from 0 mi/h and 11 mi/h were reached because the initial and final speed was 0 mi/h the speed of 10 mi/hr was reached at least twice in the race.

Step-by-step explanation:

Given,

Total distance covered = 6.2 miles,

Time taken = 34 minutes = \frac{34}{60} hours

( 1 hour = 60 minutes )

Since,

Speed = \frac{Distance}{Time}

Thus, the speed of the runner = \frac{6.2}{\frac{34}{60}}

=\frac{6.2\times 60}{34}

=\frac{372}{34}

= 10.9411764706

≈ 11 miles per hour

Thus, the average speed of the runner is 11 miles per hour ( approx )

By MVT,

The speed was exactly 10 mi/hr at least twice in the race.

By intermediate value theorem,

All speed from 0 mi/h and 11 mi/h were reached because the initial and final speed was 0 mi/h the speed of 10 mi/hr was reached at least twice in the race.

4 0
3 years ago
Pls I need it for a testI’ll give out 20 points
kompoz [17]

Answer:

It should be D.

Step-by-step explanation:

6 0
2 years ago
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