All categories

3 years ago

Can someone solve this for me? i also would like to know how you did (worked it out)

Mathematics

2 answers:

KonstantinChe [14]3 years ago

5 0

You should probably post the question so that someone is able to know what you need solved

Scilla [17]3 years ago

4 0

Can u pls try to show us the question so we can answer it and u can send it here and I will solve it ASAP

You might be interested in

In another state, all license plates consist of from four to six symbols chosen from the 26 letters of the alphabet together wit

fredd [130]

A)
First note that the plates can have between 4 and 6 symbols so we will need to find the number of plates with 4 symbols, 5 symbols and 6 symbols. We add these to get the total. In this part repetition of symbols is allowed. Since there are 26 + 10 =36 possible symbols we look at each position on the plate and think of how many choices there are. We multiply the number f choices using the counting principal since the choices are each independent -- one symbol does not affect another. There are 36 choices for the first symbol, 35 for the second and so on. The number of plates is:
4-symbols = (36)(36)(36)(36)=36^4
5 symbols = (36)^5
6 symbols = 36^6
So the total here is: 36^4+36^5+36^6

B) Here we do not repeat symbols so there are 36 choices for the first symbol but only 35 for the next and 34 for the one after and so on.
4-symbols = (36)(35)(34)(33)
5 symbols = (36)(35)(34)(33)(32)
6 symbols = (36)(35)(34)(33)(32)(31)
So the total here is: (36)(35)(34)(33)+(36)(35)(34)(33)(32)+(36)(35)(34)(33)(32)(31)

c)
In order for there to be a repeated symbol we have 36 choices for the first symbol, 36 for the next and so on. However, for the last symbol we have to pick from one of the ones already selected so there are 3, 4 or 5 choices respectively.
4-symbols = (36)(36)(36)(3)
5 symbols = (36)(36)(36)(36)(4)
6 symbols = (36)(36)(36)(36)(36)(5)
So the total here is: (36^3)(3)+(36^4)(4)+(36^5)(5)

D)
The probability is given by (the number of plates with at least one repeated symbol)/(the total number of plates if repetitions are allowed) = (the answer to c) / (the answer to a)

3 0

4 years ago

PLEASE HELP PLEASE EMERGENCY

joja [24]

1, 5, 4, 2, 3 in that order

3 0

3 years ago

Read 2 more answers

Where is the location of the vertex of the parabola on a coordinate grid?

IrinaVladis [17]

Answer:

below the x-axis

Step-by-step explanation:

y=x^2+2x-3

the vertex is located on the axis of symmetry

to find h ax^2 +bx+c

h= -b/2a = -2/2(1) = -1

the x coordinate of the vertex is -1

to find the y coordinate, substitute into the equation

y = (-1)^2 +2(-1) -3

= 1-2-3

= -4

(-1,-4)

the vertex is below the x axis

7 0

3 years ago

The thickness of metal wires used in the manufacture of silicon wafers is assumed to be normallydistributed with meanμ. To monit

yanalaym [24]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ = 10

(b) Alternate Hypothesis, $H_A$ : $\mu\neq$ 10

(c) One-sample t test statistics distribution : T.S. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

(d) The value of the test statistic is 1.054.

(e) The p-value = 0.1493

(f) We conclude that the mean equals the target value of 10 which means that the output can be considered acceptable as it doesn't differs from the target value of 10.

Step-by-step explanation:

We are given that the thickness of metal wires used in the manufacture of silicon wafers is assumed to be normally distributed with mean μ. To monitor the production process, the thickness of 40 wires is taken.

The output is considered unacceptable if the mean differs from the target value of 10. The 40 measurements yield a sample mean of 10.2 and sample standard deviation of 1.2.

Let $\mu$ = mean thickness of metal wires used in the manufacture of silicon wafers.

(a) Null Hypothesis, $H_0$ : $\mu$ = 10 {means that the mean equals the target value of 10}

(b) Alternate Hypothesis, $H_A$ : $\mu\neq$ 10 {means that the mean differs from the target value of 10}

(c) The test statistics that will be used here is One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\mu$ = sample mean = 10.2

s = sample standard deviation = 1.2

n = sample of yields = 40

(d) So, test statistics = $\frac{10.2-10}{\frac{1.2}{\sqrt{40} } }$ ~ $t_3_9$

= 1.054

The value of the test statistic is 1.054.

(e) Now, P-value of the test statistics is given by;

P-value = P( $t_3_9$ > 1.054) = 0.1493

Now at 0.05 significance level, the t table gives critical values between -2.0225 and 2.0225 at 39 degree of freedom for two-tailed test. Since our test statistics lies within the critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

(e) Therefore, we conclude that the mean equals the target value of 10 which means that the output can be considered acceptable as it doesn't differs from the target value of 10.

7 0

4 years ago

Find A∩ (B∪ C)

ololo11 [35]

Answer:

2,4

Step-by-step explanation:

(2,3)

(2,5)

(5,8)

7 0

3 years ago