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Novosadov [1.4K]
3 years ago
9

The ratio of sides of 2 similar cubes is 3:4. Larger cube has a volume of 1728 cubic meters . What is the volume of the smaller

cube?
Mathematics
1 answer:
Tanya [424]3 years ago
7 0

Answer:

729m³

Step-by-step explanation:

To find the length of one side find the cube root of 1728m³

³√1728=12metres

To find the length of the smaller cube

ratio 3:4.

4/7=12m

3/7=?

<u>3</u><u>/</u><u>7</u><u>×</u><u>1</u><u>2</u><u> </u>= 3/7×12×7/4

<u> </u><u> </u><u> </u>4/7

=9metres

To find volume of the small cube

volume=9×9×9

=729m³

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3 years ago
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
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where the coefficients are obtained by computing

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You should end up with

a_0=0
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Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

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