Answer:
b
Step-by-step explanation:
c11 = (-1) *3 + (-3)*2 + 2*(-4) = -3 - 6 - 8 = -17
C12 = (-1)*3 + (-3)*(-5) + 2*(-1) = -3 + 15 - 2 = 10
C13 = (-1)*5 + (-3) *2 + 2*1 = -5 - 6 +2 = -9
C21 = 2*3 + 5*2 + (-1)*(-4) = 6 +10 + 4 = 20
C22 = 2*3 + 5*(-5) + (-1)*(-1) = 6 - 25 + 1 = -18
C23 = 2*5 + 5 *2+ (-1)*1 = 10 + 10 -1 = 19
C31 = (-4)*3 + (- 5)*2 + (-4)*(-4) = -12 - 10 +16 = -6
C32 = (-4)*(3) + (- 5)*(-5) + (-4)*(-1) = -12 + 25 + 4 = 17
C33 = (-4)*5 + (- 5)*2 + (-4)*1 = -20 - 10 - 4 = -34
Answer:
In general, we already know how to solve problems in a right triangle using the concept of trigonometry. Meanwhile, as we also know that the type of triangle is not only a right triangle, but there are isosceles, equilateral, or even random triangles. The question is how to solve the problems that exist in these triangles It is known that there is an arbitrary triangle with sides a, b, and c. The angle formed in front of side a is called angle α, the angle formed in front of side b is called angle β, and the angle formed in front of side c is called angle γ = 5
Step-by-step explanation:
x" + 5x + 6 = 0
(x + 2)(x + 3) = 0
x + 2 = 0
x = -2
x + 3 = 0
x = -3
#semogamembantu
If you are taking the cm to km then it would be like this
4.5km*4.1cm= 18.45km
Answer: 64
Step-by-step explanation:
the Kids that answered correct in any of questions 1 and 2 got at least one right so subtract the highest number which is 81 students by all the general amount of them, 145 that’s 64.