Answer:
45.60
Step-by-step explanation:
he spent 80 × 30 = rs 2400
5 %loss means
sp= 2400 - 2400 × 0. 05
= 2280 for all remaining books so each book was sold at
2280/ 50 = 45.60
Distance between (x1,y1) and (x2,y2) is
![D= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%20)
so the distance between (7,8) and (1,-17) is
![D= \sqrt{(1-7)^2+(-17-8)^2}](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B%281-7%29%5E2%2B%28-17-8%29%5E2%7D%20)
![D= \sqrt{(-6)^2+(-25)^2}](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B%28-6%29%5E2%2B%28-25%29%5E2%7D%20)
![D= \sqrt{36+225}](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B36%2B225%7D%20)
D=√261
D=3√29
the exact distance is 3√29 units
Answer:
<h3><u>
x=0, or x=3/4, or x=1/5</u></h3>
Step-by-step explanation:
x²(4x−3)(5x−1)=0
x²=0=> x=0
4x−3=0=> x=3/4
5x−1=0=> x=1/5
<u>x=0, or x=3/4, or x=1/5</u>
Answer:
54$ is the final selling price of the camera
All of the trigonometric functions of an angle θ can be constructed geometrically in terms of a unit circle centered at O. Given that:
Sine function
![f(\theta) = sin(\theta)](https://tex.z-dn.net/?f=f%28%5Ctheta%29%20%3D%20sin%28%5Ctheta%29)
being
Cosine function
![f(\theta) = cos(\theta)](https://tex.z-dn.net/?f=f%28%5Ctheta%29%20%3D%20cos%28%5Ctheta%29)
being
We will demonstrate the identity above. First of all, we need to square each equation, so:
![sin^{2}(\theta)= v^{2}](https://tex.z-dn.net/?f=sin%5E%7B2%7D%28%5Ctheta%29%3D%20v%5E%7B2%7D)
![cos^{2}(\theta)=u^{2}](https://tex.z-dn.net/?f=cos%5E%7B2%7D%28%5Ctheta%29%3Du%5E%7B2%7D)
Adding these two equations:
![sin^{2}(\theta)+cos^{2}(\theta)=v ^{2}+u^{2}](https://tex.z-dn.net/?f=sin%5E%7B2%7D%28%5Ctheta%29%2Bcos%5E%7B2%7D%28%5Ctheta%29%3Dv%20%5E%7B2%7D%2Bu%5E%7B2%7D)
But as shown in the figure, using Pythagorean theorem
![v^{2}+u^{2}](https://tex.z-dn.net/?f=v%5E%7B2%7D%2Bu%5E%7B2%7D)
is always equal to 1, then:
![sin^{2}(\theta)+cos^{2}(\theta)=1](https://tex.z-dn.net/?f=sin%5E%7B2%7D%28%5Ctheta%29%2Bcos%5E%7B2%7D%28%5Ctheta%29%3D1)
The relation to right triangles is that:
<span>The hypotenuse is always equal to 1
</span>The opposite side is equal to
![sin(\theta)](https://tex.z-dn.net/?f=sin%28%5Ctheta%29)
The adjacent side is equal to