Let x be for unknown number. Let x be first number .
X+1 To be second number .x+2be third number. X+(x+1)+(x+2)=312.
Simplify to get 3x+3=312 . Subtract 3 from both sides 3x-3=312-3. Once you subtract get 3x=109.then divide 3 both sides . 3x/3=309/3. To get x= 103.
Now once you have that First number 103. Second number 103+1=104 . And third number 103+2=105. To check add them 103+104+105=312
Answer:
8x - 14 = 5x + 34 (alternate exterior angles)
8x - 5x = 34 + 14
3x = 48
x = 48/3
x = 16
5y + 16 + 8x - 14 = 180 (linear pair)
5y + 16 + 8(16) - 14 = 180
5y + 16 + 128 - 14 = 180
5y + 130 = 180
5y = 180 - 130
5y = 50
y = 50/5
y = 10
∠ (8x - 14) = 114 [(8 × 16 -14)=114]
∠ (5x + 34) = 114 [(5 × 16 +34)=114]
∠ (5y + 16) = 66 [(5 × 10 +16)=66]
hope this helps you!
