-7 - 8 - (-8) - 7 × 0(14) - 14 - 30
(I think that's what that says)
Do PEMDAS
0(14) = 0
-7 × 0 = 0
You're left with -7 - 8 - (-8) - 14 - 30
Go from left to right
-7 - 8 = -15
-15 - (-8) = -7
-7 - 14 = -21
-21 - 30 = -51
 
        
                    
             
        
        
        
Answer:
  
 
 
  

Step-by-step explanation:
Let E be the set of all even positive integers in the universe Z of integers,
i.e 
E = {2,4,6,8,10 ....∞}
 be the characteristic function of E.
 be the characteristic function of E.
∴

For XE(2) 
  since x is an element of E (i.e the set of all even numbers)
  since x is an element of E (i.e the set of all even numbers)
For XE(-2) 
 since  - 2 is less than 0 , and -2 is not an element of E
   since  - 2 is less than 0 , and -2 is not an element of E
For { x ∈ Z: XE(x) = 1}
This can be read as:
x which is and element of Z such that X is also an element of x which is equal to 1.
∴

E = {2,4,6,8,10 ....∞}
 
        
             
        
        
        
The answer is 3 jehfhdhhedhhshshdhhsgdjshshdhdh
        
             
        
        
        
F (x)= (x+1)(x-1)(x^2-2x-2)
        
             
        
        
        
 Answer:
Parallel 
Step-by-step explanation:
They're Parallel because whenever you graph them you see they never touch.