Answer:
Explanation:
A woman who is a carrier for #1 hemophilia and a man that does not have the
condition have children. What is the probability that they will have a child
with the condition being studied? What is the gender of that child?
if the baby gets the Y chromosome from the father it will be a boy. If the boy gets his mother's X chromosome with the hemophilia gene he will have hemophilia. If he inherits his mother's other X chromosome, he will have normal blood clotting. If the baby gets the X chromosome from the father it will be a girl.
#4 A woman that is heterozygous for type A blood and a man that is heterozygous for type B blood have children. What are the possible blood types of their children?
One parent with A and another with B can produce a child with A, B, AB or O blood types.
#5 Two people are both unknowingly carriers for the cystic fibrosis gene. What is the probability that they will have children with cystic fibrosis?
If both parents are carriers there is a 1 in 4 (25 percent) chance that both will pass on the non-functioning gene, which would result in a pregnancy affected with cystic fibrosis.
#3 A woman that is heterozygous for Huntington's disease and a man that does not have the condition have children . What is the probability that their children inherit the Huntington's gene ?
Huntington's disease (HD) is what is called a dominant genetic disease. What this usually means is that a child only has a chance of getting a disease like this if a parent has it too. But parents without HD can have a child with HD. This is true of any dominant genetic disease
<span>through the urethra to the postrate
Sperm at that point goes through the deferent channel through up the spermatic rope into the pelvic depression, over the urethra to the prostate . Here, the vas deferens joins with the fundamental vesicle to shape the ejaculatory channel, which goes through the prostate and exhausts into the urethra. At the point when discharge happens, muscle action impel the sperm forward.</span>
Answer: Without other information, the number of animals maybe between 19-73 depending on age and pancreas size. Of the options presented, the nearest answer is D.32
Explanation: Assumptions
2yo cow with pancreas 400g
insulin content ~5 IU (175ug)
Daily insulin requirement 0.5-1 IU —> 187-365 IU p.a.
beef animals required 37-73 cows
using 6 mo calves, the insulin content is ~10IU, so requiring 19-37 calves
Answer:
Tt = 50%
tt = 50%
tall = 50%
short = 50%
<em>I hope this helps you</em>
<em>:)</em>