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2 years ago

HELP ASAP!!

Mathematics

2 answers:

Sladkaya [172]2 years ago

7 0

Step-by-step explanation:
given; circumference =17. 27ft
radius=?
radius=circumference/6.28
radius=17.27/6.28=2.75 ft
Answer=B.2.75 ft

Soloha48 [4]2 years ago

3 0

Answer:

¯\_(ツ)_/¯

Step-by-step explanation:

¯\_(ツ)_/¯

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Write each word phrase as an algebrale

dedylja [7]

66) ten less than a number

Let the number be n

= n - 10

67) the product of x and y

= x × y or xy

68) The algebraic expression for ten less than n

= n - 10

Must click thanks and mark brainliest

8 0

3 years ago

Evealute the expression when m= -2 m^2+9m+3

Volgvan

Step-by-step explanation:

m=-2

m^2+9m+3

substitute-2 in m

-2^2+9(-2)+3

= -19

8 0

2 years ago

Find the area of the region that lies inside the first curve and outside the second curve.

marishachu [46]

Answer:

Step-by-step explanation:

From the given information:

r = 10 cos( θ)

r = 5

We are to find the the area of the region that lies inside the first curve and outside the second curve.

The first thing we need to do is to determine the intersection of the points in these two curves.

To do that :

let equate the two parameters together

So;

10 cos( θ) = 5

cos( θ) = $\dfrac{1}{2}$

$\theta = -\dfrac{\pi}{3}, \ \ \dfrac{\pi}{3}$

Now, the area of the region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e

$A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} (10 \ cos \ \theta)^2 d \theta - \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ 5^2 d \theta$

$A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} 100 \ cos^2 \ \theta d \theta - \dfrac{25}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ d \theta$

$A = 50 \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix} \dfrac{cos \ 2 \theta +1}{2} \end {pmatrix} \ \ d \theta - \dfrac{25}{2} \begin {bmatrix} \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}}$

$A =\dfrac{ 50}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix} {cos \ 2 \theta +1} \end {pmatrix} \ \ d \theta - \dfrac{25}{2} \begin {bmatrix} \dfrac{\pi}{3} - (- \dfrac{\pi}{3} )\end {bmatrix}$

$A =25 \begin {bmatrix} \dfrac{sin2 \theta }{2} + \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{\dfrac{\pi}{3}} \ \ - \dfrac{25}{2} \begin {bmatrix} \dfrac{2 \pi}{3} \end {bmatrix}$

$A =25 \begin {bmatrix} \dfrac{sin (\dfrac{2 \pi}{3} )}{2}+\dfrac{\pi}{3} - \dfrac{ sin (\dfrac{-2\pi}{3}) }{2}-(-\dfrac{\pi}{3}) \end {bmatrix} - \dfrac{25 \pi}{3}$

$A = 25 \begin{bmatrix} \dfrac{\dfrac{\sqrt{3}}{2} }{2} +\dfrac{\pi}{3} + \dfrac{\dfrac{\sqrt{3}}{2} }{2} + \dfrac{\pi}{3} \end {bmatrix}- \dfrac{ 25 \pi}{3}$

$A = 25 \begin{bmatrix} \dfrac{\sqrt{3}}{2 } +\dfrac{2 \pi}{3} \end {bmatrix}- \dfrac{ 25 \pi}{3}$

$A = \dfrac{25 \sqrt{3}}{2 } +\dfrac{25 \pi}{3}$

The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.

Download docx

7 0

2 years ago

Can someone help pleas

Lena [83]

Step-by-step explanation:

According to picture 1, it is A. corresponding.

Also according to picture 2, it is E. same side interior.

And according to picture 3, it is D. vertical

6 0

2 years ago

Need help quick simplify the expression (-4) power of 3

dezoksy [38]

Answer:

-64

Step-by-step explanation:

The question is asking to solve $(-4)^3$

Notice how the -4 is in parenthesis. This means that along with the 4 being multiplied, the negative is too.

$(-4)^3$ is the same as -4 · -4 · -4

First let's figure out if this will be negative or positive

Whenever the exponent is odd and there is a negative in the parenthesis the answer will be negative and if its even it will be positive

Now find out what 4 x 4 x 4 equals (64)

In conclusion the answer is -64

8 0

2 years ago