1/5k+ 15
= 1/5k+ 15* (5/5) (because 5/5= 1)
= 1/5k+ (15*5)/ 5
= 1/5k+ 75/5
= 1/5k+ 75* (1/5)
= 1/5(k+ 75) (distributive property)
The final answer is 1/5(k+ 75).
0.75 x 14 = 10.50
15 - 10.50 = 4.50
your answer is : Sharon will receive $4.50 change
Answer:
To be precise, I think it's a pattern question, where you have to add 4 to each number. I'm not very sure though.
Answer:
Step-by-step explanation:
10000*4%= 400 Geese year1
10400*4%=416 Geese year 2
10816*4%= 432.64 Geese year 3
11,248.64*4%= 449.95 Geese. year 4
11248.64+449.95= 11698.59
11698.59-10000=1698.59
Increased by 1699 Geese.
Answer:
The estimated probability that Ginger will eat a a pizza everyday of the week is;
D. 8/10 = 80%
Step-by-step explanation:
The given parameters are;
The frequency with which Ginger buys launch = Everyday
The percentage of the time the cafeteria has pizza out = 80%
The outcome of 0 and 1 = No pizza available
The outcome of 2, 3, 4, 5, 6, 7, 8, and 9 = Pizza available
Therefore, we have the;
Group number
Percentage of time pizza available
1
80%
2
80%
3
80%
4
80%
5
40%
6
100%
7
80%
8
100%
9
80%
10
80%
Therefore, the sum of the percentages outcome the days Ginger eats pizza = 0.8 + 0.8 + 0.8 + 0.8 + 0.4 + 1 + 0.8 + 1 + 0.8 + 0.8 = 8
The number of runs of simulation = 10 runs
The estimated probability that Ginger will eat a a pizza everyday of the week = (The sum of the percentages outcome the days Ginger eats pizza)/(The number of runs of simulation)
∴ The estimated probability that Ginger will eat a a pizza everyday of the week = 8/10