In a population of 10,000 geese the growth rate is 4% per year. What is the total increase in population over 4 years? Round you
2 answers:
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Answer:
Step-by-step explanation:
The initial number of mosquitoes is 400000, and they double each day. This represents an exponential growth equation. If t represent days and P represent the population of the mosquitoes, hence this can be represented by the equation:
Also, the predators eat the mosquitoes at a rate of 40,000 mosquitoes/day. This means that each day, the mosquitoes reduce by 40000t, therefore this can be represented by: