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2 years ago

Me on my block be like

Business

2 answers:

Volgvan2 years ago

7 0

Answer:

facttttttsssssssssssssssssssssssss XD

have a good day :)

Explanation:

guajiro [1.7K]2 years ago

5 0

Answer:

this is tru because

Explanation:

yesss so tru yas queeeen

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If employees are told that budgets must be cut by 10 percent, they may automatically assume that 10 percent of employees will lo

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Answer: This tendency to make assumptions is referred to as CLOSURE.

Explanation: CLOSURE is defined as the experience of an emotional conclusion usually to a difficult period. This is usually done bearing in mind that the experience is open to more than one meaning, interpretation or explanation. In this case, the information given to the employees is a polysemy/ambiguous making their assumptions referred to as closure.

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3 years ago

In the context of foreign market entry, ________ requires no equity investment and thus has a low risk, low rate of return, and

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it is B because franchising is the best option

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3 years ago

Read 2 more answers

Larry Ellison starts a company that manufactures high-end custom leather bags. He hires two employees. Each employee only begins

Degger [83]

Answer:

12.55 days

Explanation:

Provided information

Number of employees 2

Average production time=1.8 days

Standard deviation=2.7 days

Inter-arrival time= 1 day

Coefficient of variation= 1 day

Standard deviation of inter-arrival time= 1 day

The coefficient of variations

Inter-arrival coefficient of variation

$C_{vi}=\frac {\sigma}{T}$ where $\sigma$ is standard deviation of inter-arrival time, T is inter-arrival time and $C_v$ is coefficient of variation of inter-arrival time

$C_{vi}=\frac {1 day}{1 day}=1$

Production time coefficient of variation

$C_{vp}=\frac {2.7}{1.8}=1.5$

Total utilization time

$U=\frac {T}{n*T_i}$ where T is the time of production, n is number of employees, U is utilization, $T_i$ is inter-arrival time

$U=\frac {1.8}{2*1}=0.9$

Therefore, utilization time by 2 employees is 0.9

Expected average waiting time

$T_e=(\frac {T}{n*T_i})*0.5(C_{vi}^{2}+C_{vp}^{2})*(\frac{U^{\sqrt{2(n+1)}-1}}{1-U})$

Where $T_e$ is expected average waiting time and the other symbols as already defined

Substituting 1.5 for $C_{vp}$ , 1 for $C_{vi}$ , 0.9 for U, 2 for n, 1 for $T_i$ and 1.8 for T

$T_e=(\frac {1.8}{2*1})*0.5(1^{2}+1.5^{2})*(\frac{0.9^{\sqrt{2(2+1)}-1}}{1-0.9})$

$T_e=0.9*1.625*8.583709=12.55367 days$ and rounding off to 2 decimal places we obtain 12.55 days

Therefore, expected duration between order received and beginning of production is approximately 12.55 days

7 0

3 years ago

UA Hamburger Hamlet (UAHH) places a daily order for its high-volume items (hamburger patties, buns, milk, and so on). UAHH count

Assoli18 [71]

Answer:

730 items

Explanation:

The objective of the given information is to determine the number of hamburgers UAHH should order for the following conditions:

Average daily demand 600

Standard deviation of demand 100

Desired service probability 99%

Hamburger inventory 800

The formula for a given order quantity in a fixed period of time can be expressed as :

$q = \overline d(L+T)+ z \sigma_{L+T}-I$

where;

$q$ = order quantity = ???

$\overline d$ = daily demand average = 600

L = lead time in days = 1

T = time taken = 1

z = no of standard deviation = ???

$\sigma_{L+T}$ = standard deviation of usage in lead time and time taken = ???

I = present inventory level = 800

$\sigma_{L+T}$ = $\sqrt 2$ × standard deviation of daily demand

$\sigma_{L+T}$ = $\sqrt{2} *100$

$\sigma_{L+T}$ = 1.4142 * 100

$\sigma_{L+T}$ = 141.42 items

From the Desired service probability 99% = 0.99; we can deduce the no of standard deviation by using the excel function (=NORMSINV (0.99))

z = 2.33

From $q = \overline d(L+T)+ z \sigma_{L+T}-I$

$q =600(1+1)+ 2.33*(141.42)-800$

$q =600(2)+ 2.33*(141.42)-800$

$q =1200+329.5086-800$

q = 729.5086 items

q ≅ 730 items

Therefore; the number of hamburgers UAHH should order from the following given conditions = 730 items

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3 years ago

A next monthly interest payment on a loan with a principal balance of $19,531 is $109.86. what is the interest rate on the loan?

8_murik_8 [283]

The next monthly interest payment on a loan with a principal balance of $19,531 is $109.86. 6.75% is the interest rate on the loan.

The interest rate is the percentage of the loan that the borrower pays to the lender. Most loans pay interest in addition to the principal. Lending rates are usually expressed in his APR or APR which includes both interest and fees.

Monthly Interest Payment means the amount of interest payable on the Payment Date for the preceding Interest Period based on the interest calculated at the Monthly Interest Rate for the preceding Interest Period.

Interest is an additional payment known as interest on top of the principal paid to a lender for the right to borrow money.

Learn more about monthly interest payment at

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2 years ago