The total weight of candies is unknown. Let x = the total weight of candies.
"One student ate 3/20 of all candies and another 1.2 lb":
The first student ate (3/20)x plus 1.2 lb which is 0.15x + 1.2.
"The second student ate 3/5 of the candies and the remaining 0.3 lb."
The second student ate (3/5)x and 0.3 lb which is 0.6x + 0.3.
Altogether the 2 students ate 0.15x + 1.2 + 0.6x + 0.3.
That was all the amount of candies, so that sum equals x.
0.15x + 1.2 + 0.6x + 0.3 = x
Now we solve the equation for x to find what the total amount of candies was.
0.75x + 1.5 = x
-0.25x = -1.5
x = 6
The total amount of candies was 6 lb.
The first student ate 0.15x + 1.2 = 0.15(6) + 1.2 = 0.9 + 1.2 = 2.1, or 2.1 lb of candies.
The second student ate 0.6x + 0.3 = 0.6(6) + 0.3 = 3.6 + 0.3 = 3.9, or 3.9 lb of candies.
Answer: The first student ate 2.1 lb of candies, and the second student ate 3.9 lb of candies.
Answer:
A, B, and C
I think. Please let me know if wrong.
Heres what i did:
1.8 x 100 = 180.
180 - 80 = 100
(they made over 100 in profit)
A. 1.2 x 0 = 0
B. 1.2 x 40 - 48
C. 1.2 x 60 = 72
D. 1.2 x 70 = 84
E. 1.2 x 80 =96
D and E bot Exceed 80 so it has to be AB and C
Hope this Helps ☺
You should have put a picture so we could see the graph
Answer: im not completley sure but , i think its 10
Step-by-step explanation:
Answer:
y=-2/5x+1
y=x+1
y=249/10
y=23
y=x+5
Step-by-step explanation:
Let's solve for x.
y=x+5
Step 1: Flip the equation.
x+5=y
Step 2: Add -5 to both sides.
x+5+−5=y+−5
x=y−5
Answer:
x=y−5
