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3 years ago

How do you find the perimeter of any closed figure?

1 answer:

5 0

You can find the perimeter of any closed figure by, measuring the sides and adding all of the sides. After, you have to add all of the sides, including the base together! Hope this is correct

You might be interested in

Should the quotient of an integer divided by a nonzero integer always be a rational number? Why or Why not?

lubasha [3.4K]

Yes, it will always be a rational number. I'll expound on this by defining what a rational number is. It is any number that can be expressed as a fraction. Otherwise, it is called an irrational number with a non-terminating decimal expansion. So, although 1/3 has a non-terminating decimal expansion because it is equal to 0.33333333...., it is still a rational number because it can be expressed into a fraction.

8 0

3 years ago

Anyone know this problem???

sammy [17]

Answer:

Step-by-step explanation:

$\frac{28}{11}$ = 2.54545454.....

The repeating digits are 54 ← group of 2

4 0

2 years ago

Read 2 more answers

...................................................

snow_lady [41]

Answer:

3x + 2 = 59

Step-by-step explanation:

because the total is 59 so is definetly =59

and no of oranges in bag so there are 3 bags it means its 3x so the equation is 3x + 2 = 59

Hope it will help you

Lots of love from nepal <3 :)

5 0

2 years ago

40 is 80% of what number?

agasfer [191]

Answer:

Step-by-step explanation:

.80n = 40

n = 40 divided by .80

40/8/10 = 400 / 80 = 50

Best Of Luck,

- I.A. -

6 0

2 years ago

Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and <br> x + 7y = 8

goblinko [34]

$\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y = \frac{17}{14} } \atop {x+7y=8}} \right.$

To solve this system by substitution, first isolate x in the second equation.

$x+7y=8$
$x+7y-7y=8-7y$
$x=8-7y$

Now, plug this expression ( $8-7y$ ) for x in the top equation to solve for y.

$\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}$
$3- \frac{21}{8} y+ \frac{1}{3} y= \frac{17}{24}$
$72-63y+8y=17$
$72-55y=17$
$-55y=17-72$
$-55y=-55$
$y=1$

Now that you have y, plug it into the second equation and solve for x.

$x+7y=8$
$x+7(1)=8$
$x+7=8$
$x=1$

Last step is to plug your x- and y-values in to both equations to check your work.

$\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}$

$\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ; \frac{1}{3} * \frac{8}{8} = \frac{8}{24}$

$\frac{9}{24} + \frac{8}{24} = \frac{17}{24}$ <--True

$1+7(1)=8$
$1+7=8$ <--True

Answer:
$x=1 \\ y=1$

5 0

3 years ago