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bixtya [17]
2 years ago
8

HELPPPP PLSSSSSSSSSSSSSSSSSSSS

Mathematics
1 answer:
forsale [732]2 years ago
5 0

Answer:

.um g o o g l e look it u p I do that.

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F(x)=8x^2-2x+3<br> g(x)=12x^2+4x-3<br> what is h(x)=f(x)-g(x)?
Trava [24]

Answer: h(x)=-4x^2-6x+6

Step-by-step explanation:

To find the function h(x), you need to subtract the function f(x)=8x^2-2x+3 and the function g(x)=12x^2+4x-3.

h(x)=f(x)-g(x)\\h(x)=8x^2-2x+3-(12x^2+4x-3)

Distribute the negative sign:

h(x)=8x^2-2x+3-12x^2-4x+3

Now you can add the like terms:

h(x)=-4x^2-6x+6

Therefore, you get that the function h(x) is:

 h(x)=-4x^2-6x+6

6 0
3 years ago
Read 2 more answers
Find the zeros of x^2+4x=-10 using the quadratic formula
ipn [44]
X^2+4+10=0
x=(-4(+/-)root16-40)/2, so we now know that the zeros are imaginary, because you can't square root a negative number and 16-40 is -24
so the two roots are…
-2+iroot6 and -2-iroot6

7 0
3 years ago
Read 2 more answers
Find the ratio a:b, if 2a−b/6 = b/3
Tom [10]

Answer:

a:b = 2

Step-by-step explanation:

Here we need to operate with terms in order to arrive to a ratio a:b (or a/b).

We have:

2a−b/6 = b/3

Lets sum b/6 in both sides:

2a−b/6 + b/6 = b/3 + b/6

2a = b/3 + b/6

Now, we can multiply and divide b/3 by 2 to make a 6 appear on the denominator and sum it with b/6, this is, use common denominator:

2a = b/3*(2/2) + b/6

2a = 2b/6 + b/6

2a = 3b/6

2a = b/2, as 3/6 = 1/2

Now lets divide both sides by b to make an a/b appear:

2a/b = (b/2)/b

2a/b = 1/2

Finally, multiply both sides by (1/2) or divide by 2:

(2a/b)/2 = 2

a/b = 2

This is, a is twice as b. If b is 1 so a is 2; if b is 45 so a is 90, and so on.

7 0
3 years ago
Number 3 please need help
kirza4 [7]
Im pretty sure it would be 4

4 0
3 years ago
PLEASE HELP<br><br><br> h(1) =<br> and h(4) =
Alekssandra [29.7K]
Putting in h(1) would get you 1, putting in h(4) would get you 5.
4 0
3 years ago
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