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3 years ago

Round yo The nearest ten 834,692. Help me please!!

Mathematics

2 answers:

Genrish500 [490]3 years ago

8 0

The answer should be 834, 690

hope this helps!

nasty-shy [4]3 years ago

6 0

834,69<u>2</u>

If the number is less than 5, you keep the the 90 the same.

If the number is more than 5, the new number would be <u>834,700.</u>

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<u>The answer is </u>

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What are all the composite numbers from 1 to 100

Anastaziya [24]

Answer:

4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80, 81,82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99, 100.

Step-by-step explanation:

its pretty simple...

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3 years ago

The graph of the line y= 3 is a line that has which of the following characteristics?

vaieri [72.5K]

Answer:

Step-by-step explanation:

4 0

3 years ago

I need help with this, please!

Vera_Pavlovna [14]

Option D: $x \geq 3$ is the solution

Explanation:

The given expression is $3 x-1 \geq 8$

We need to determine the solution of the expression.

<u>Solution:</u>

The solution of the expression can be determined by solving the expression for the variable x.

Thus, we have,

$3 x-1 \geq 8$

Adding both sides of the expression by 1, we get,

$3x\geq 9$

Dividing both sides of the expression by 3, we get,

$x \geq 3$

Thus, the solution of the expression is $x \geq 3$

Hence, Option D is the correct answer.

6 0

3 years ago

A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.

pav-90 [236]

Answer:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.25$ represent the population standard deviation

n represent the sample size

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got: