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ludmilkaskok [199]
3 years ago
5

The number of suitcases on a flight caring 250 passengers. Round to the nearest whole number of suitcases and enter your answer

as a number only. 

Mathematics
1 answer:
stiks02 [169]3 years ago
6 0

Answer:

  • The number of suitcases are 503.

Step-by-step explanation:

<u>Given that</u>:

  • The number of suitcases on a flight caring 250 passengers.

<u>To Find</u>:

  • The number of suitcases.

<u>Equation</u>:

  • y = 1.98x + 7.97

Where,

  • x = Number of passengers
  • y = Number of suitcases

<u>Finding the number of suitcases</u>:

⟶ y = 1.98x + 7.97

⟶ y = 1.98(250) + 7.97

⟶ y = 495 + 7.97

⟶ y = 502.97 ≈ 503

<u>Hence</u>,

  • The number of suitcases are 503.
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1.

a. true

b. false (the arc angles are relative to the center of the circle)

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d. true (but note that the arc angle of YE is again measured via the center of the circle and twice as large as the angle S)

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EGS is an isoceles triangle (that means both legs are equally long).

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c being the side opposite of the angle C.

let's say c is our long baseline, since we have is opposite angle 124°, and a = b = GE = GS, we have

3.8² = a² + a² - 2aa×cos(124) = 2a² - 2a²×cos(124) =

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a² = 3.8²/(2(1 - cos(124)))

a = GS = sqrt(3.8²/(2(1 - cos(124)))) =

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yes, the statement is true.

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a half-circle has 180°.

the arc angel AD is a full half-circle (because AD is a diameter), so it is 180°.

the angle ACB is the arc angle AB = 40°. so, the arc angle BD must be the rest of the 180° = 180 - 40 = 140°.

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diameter = 50 ft.

so, the radius or distance from the center to the circle arc is 50/2 = 25 ft.

the length of a chord is

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40 = 2×sqrt(25² - d²)

20 = sqrt(625 - d²)

400 = 625 - d²

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225 = d²

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so, the distance of the chord from the center is 15 cm.

6.

the arc angles RE and TS are equal. that means the arc lengths of RE and TS are equal.

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7.

they are equally long.

as we saw in 5., the length of a chord depends on the radius of the circle and the distance of the chord from the center.

since both chords are in the same circle (with the same radius), and they both have the same distance from the center, they can only be equally long, as there is no other element to name them different.

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