This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
3
Step-by-step explanation:
by question
5x+2=17
5×=15
×=3
Answer:
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Answer:
y=5x-12
Step-by-step explanation:
The general equation of a line is <em>y=mx+b</em>.
The equation you currently have is <em>y=5x+b</em>.
Plug in the point (3,3) which will get you <em>3=5(3)+b</em>.
Solve the equation by solving what the y-intercept (b) is to create the new final equation.
3=5(3)+b
3=15+b
b=3-15
b=-12
y=5x-12
