Please Help FAST! SOLVE EACH! Can I get step by steps also so I can understand thx I’ll mark brainlist also!!!

Mathematics

1 answer:

professor190 [17]2 years ago

7 0

X-6y=6 slope: 1/6 y-intercept (0,1)

X= 0,6 y= -1, 0
X+3y+12=0 slope: 1/3
Y-intercept (0,4) x= -12, 0 Y= 0,4
8a-9b= 9/8 slope (0 ,7/8) x= -1,1 Y= -1/4,2
3a+b=7 1/3 (0,7/3) x= 4,7 Y=1,0

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Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)

Leni [432]

Alrighty

remember some rules
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}=\frac{1}{x^m}$
and
$x^0=1$ for all real values of x
and
$(a^b)^c=a^{bc}$
and
$(\frac{a}{b})^c=\frac{a^c}{b^c}$
and
(a/b)/(c/d)=(ad)/(bc)
and
$(a^b)(a^c)=a^{b+c}$
and
$\frac{a^m}{a^n}=a^{m-n}$
and don't forget pemdas
example: $-x^m=-1(x^m)$ but $(-x)^m=(-1)^m(x^m)$

so

4.
$(\frac{c^{-2}}{2})^{-2}=$

$\frac{(c^{-2})^{-2}}{2^{-2}}=$

$\frac{c^4}{\frac{1}{2^2}}=$

$\frac{c^4}{\frac{1}{4}}=$

$4c^4$

5.

$\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=$

$\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=$

$\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=$

$\frac{(a^4bc^5)b^3}{(-1)(a^2)}=$

$\frac{-a^4b^4c^5}{a^2}=$

$-a^2b^4c^5$

3 0

2 years ago

13) The side length of the following cube is 8 cm. what is the length of the diagonal through its center?

Scorpion4ik [409]

Answer: $\sqrt{3}$ x 8 = 13.8564064606

Step-by-step explanation: The main diagonal of any cube can be found by multiplying the length of one side by the square root of 3 ( $\sqrt{3}$ ). Therefore, square root 3 ( $\sqrt{3}$ ) is multiplied by the length (8 in our case) of either 6 faces of the cube.

Hope it helped!

5 0

2 years ago

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The sum of two numbers is 840. One of the numbers is 357. What is the other number?

Ksivusya [100]

We can create a formula first.

X will be the unknown number

840= 357+x
-357 -357

483 = x

Hope this helps

7 0

2 years ago

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If a triangle is equilateral, then all the sides in the triangle are congruent.If all the sides in a triangle are congruent, the

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