I assume you mean pi.
If my phone bill is calculated using equation c= 50g +75 what is the value and interpretation of the slope of this equation? C=
1 answer:
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Answer: p-value is 0.016.
Step-by-step explanation:
Since we have given that
Sample mean = 19.4
Sample size n = 50
Standard deviation = 2
We need to find the test statistic value which is given by
p-value is given by
Hence, p-value is 0.016.
Answer:
Step-by-step explanation:
A suitable common denominator is 4k^2. (This eliminates the first and last choices.)
Answer:
(a) <em>H</em>₀: <em>μ ≥ 5.70 </em><em>vs. </em><em>Hₐ</em>:<em>μ < 5.70</em>
(b) The rejection region is (<em>t₀.₀₁,₉</em> <em>≤ -2.821</em>).
(c) The value of the test statistic is -4.33.
(d) The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.
Step-by-step explanation:
A hypothesis test should be conducted to determine that the if the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.
(a)
The hypothesis is:
<em>H</em>₀: The true mean breaking strength of the new bonding adhesive is not less than 5.70 Mpa, i.e. <em>μ ≥ 5.70</em><em>.</em>
<em>Hₐ</em>: The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa, i.e. <em>μ < 5.70</em><em>.</em>
(b)
The alternate hypothesis indicates that the hypothesis test is left-tailed.
The rejection region for the left tailed test will be towards the lower tail of the t<em>-</em>distribution curve.
The significance level of the test is: <em>α</em> = 0.01.
The critical value is:
Use the <em>t-</em>table for the critical value.
Since rejection region is in the lower tail the critical value will be negative.
Thus, the rejection region is (<em>t₀.₀₁,₉</em> <em>≤ -2.821</em>).
(c)
The test statistic value is:
Given:
Compute the value of the <em>t</em>-statistic as follows:
The value of the test statistic is -4.33.
(d)
The value of the test is less than the critical value.
This implies that the test statistic lies in the rejection region.
Hence the null hypothesis will be rejected at 1% significance level.
<u>Conclusion:</u>
As the null hypothesis is rejected it can be concluded that the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.
(e)
The conditions required for the <em>t-</em>test for single mean to be valid is:
- The data should be continuous.
- The parent population should be normally distributed.
- The sample should be randomly selected.