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omeli [17]
3 years ago
10

Suppose that a dart board is given by a circle of radius 1 in R², centered at (0,0). You throw a dart at the dart board, and the

position that it lands is given by a pair of random variables, (X,Y).
a. Suppose that the probability of a "Bull's Eye" is zero; that is, P(X = 0, y = 0) = 0.
b. Prove that there must be some integer n > 0 such that P (√X^2 +Y^2 > 1/2) > 0.
Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0

Answer:

Answer B

Step-by-step explanation:

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Help needed please , I do not understand
luda_lava [24]
I don’t understand it too lol
3 0
3 years ago
Create a four types of two steps each with different operation. Solve them and explain the steps
Luba_88 [7]

Answer:

4 + 5 = 9

9 – 5 = 4

9 – 5 ≠ 5 – 9

9 – 4 = 9 + (–4)

6 0
3 years ago
At a 3​-mile ​cross-country race, an athlete runs 2 miles at 6 mph and 1 mile at 12 mph. What is the​ athlete's average​ speed?
Tom [10]

Answer: the average speed is 7.5 mph or at least im pretty sure

Step-by-step explanation:

This is because if you make the 2 miles at 6 mph to 1 mile at 3 mph then you get 1 mile at 3mph and 1 mile at 12 mph. now that you have the unit rates of these you can add them. 1 + 1 = 2 miles and 3 + 12 = 15 mph now divide this by two and you get 7.5 mph per mile.

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8 0
3 years ago
48 lbs. equals how many kilograms?
Dahasolnce [82]
Your answer is 21.7724<span>Kilograms</span>
4 0
3 years ago
Read 2 more answers
100 POINTS, WILL MARK BRAINLIEST! If h(x) = f[f(x)] use the table of values for f and f ′ to find the value of h ′(1).
victus00 [196]

Answer:

The value of h^\prime(1)=5

Step-by-step explanation:

Given that  h(x)=f(f(x))

now to find h(x)=f(f(x)) from the given functions f(x) and f'x

let h(x)=f(f(x))

Then put x=1 in above function we get

h(1)=f(f(1))

=f(3) (from the table f(1)=3 and f(3)=6)

Therefore h(1)=6

Now to find h'(1)

Let

h^{\prime}(x)=f^{\prime}(f^\prime(x)) (since  h(x)=f(f(x)) )

put x=1 in above function we get

h^{\prime}(1)=f^{\prime}(f^\prime(1))

=f^{\prime}(2)    (From the table f^\prime(1)=2 and f^\prime(2)=5)

h^{\prime}(1)=5

Therefore h^{\prime}(1)=5

4 0
3 years ago
Read 2 more answers
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