Answer:
F = 29.9 N
Explanation:
It is given that, The Sun exerts a gravitational force of 29.9 N on a rock that's located in a river bed here on Earth. We need to find the gravitational force the rock exert on the Sun. It is a case of Newton's third law of motion which states that the force acting from one object to another is equal to the force acing from second object to the first object and the two forces must be in opposite direction. Hence, the gravitational force the rock exert on the Sun is same i.e. 29.9 N.
Answer:
Explanation:
Given
mass of disk 
diameter of disc 
Force applied 
Now this force will Produce a torque of magnitude



And Torque is given Product of moment of inertia and angular acceleration 

Moment of inertia for Disc 



If the mass of the sun is 1x, at least one planet will fall into the habitable zone. if I place a planet in orbits 2, 6, and 75, and all planets will orbit the sun successfully.
If the mass of the sun is 2x, at least one planet will fall into the habitable zone. if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully.
If the mass of the sun is 3x, at least one planet will fall into the habitable zone if I place a planet in orbits 672, and 7 and all planets will orbit the sun successfully.
velocity and wavelength are likely to change in the process
- When a wave travels from one medium to another it undergoes a change in direction and this is referred to as refraction.
- Refraction is the bending of a wave or a change in direction of a wave as it travels from one medium to another. Refraction is accompanied by change in velocity and wavelength of a wave
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Answer:
A) If one travels around a closed path adding the voltages for which one enters the negative reference and subtracting the voltages for which one enters the positive reference, the total is zero.
Explanation:
Kirchhoff's voltage law deals with the conservation of energy when the current flows in a closed-loop path.
It states that the algebraic sum of the voltages around any closed loop in a circuit is always zero.
In other words, the algebraic sum of all the potential differences through a loop must be equal to zero.