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3 years ago

3. There is a thin layer of water between the blade and the ice. Suggest how this affects friction and helps the skater? .

Physics

1 answer:

Deffense [45]3 years ago

8 0

Explanation:

Underneath the blade of skates, there is a thin layer of water from the melted ice. ... This water then acts as a lubricant (something whose purpose is decreasing friction), resulting in a smooth motion of the skates over the ice.

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our iclicker operates at a frequency of approximately 900 mhz (900x106 hz). what is the approximate wavelength of the em wave pr

Elena-2011 [213]

wavelength of the EM wave produced by your iclicker is 0.33 m.

<h3>What makes an EM wave?</h3>

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The clicker emits EM (electromagnetic) wave which travels at the speed of light, that is

v = 3 x 10⁸ m/s

The frequency is

f = 900mHz = 9 x 10⁸ Hz

velocity = frequency * wavelength, the wavelength, λ, is given by

fλ = v

λ = v/f

= (3 x 10⁸ m/s) / (9 x 10⁸ 1/s)

= 1/3 m = 0.333 m

To learn more about electromagnetic waves refer,

brainly.com/question/25847009

#SPJ1

6 0

1 year ago

A grandfather clock has a pendulum that consists of a thin brass disk of radius r = 13.62 cm and mass 1.199 kg that is attached

Feliz [49]

Answer:

Explanation:

Expression for time period of a pendulum is as follows

T = $2\pi\sqrt{\frac{l}{g} }$

l is length of pendulum from centre of bob and g is acceleration due to gravity

Given

Time period T = 1.583

g = 9.846

Substituting the values

1.583 = $2\pi\sqrt{\frac{l}{9.846} }$

l = $\frac{(1.583)^2\times9.846}{4\times(\frac{22}{7})^2 }$

l = .6244 m

= 62.44 cm

Length of rod = length of pendulum - radius of bob

= 62.44 - 13.62

= 48.82 cm

= .488 m

8 0

3 years ago

2. How is frequency described in mathematical terms?

alexdok [17]

Answer:

Explanation:

Frequency refers to the number of occurrences of a periodic event per time and is measured in cycles/second. In this case, there is 1 cycle per 2 seconds. So the frequency is 1 cycles/2 s = 0.5 Hz.

4 0

3 years ago

Read 2 more answers

A metal can containing condensed mushroom soup has mass 215 g, height 10.8 cm, and diameter 6.38 cm. It is placed at rest on its

s344n2d4d5 [400]

Answer:

Part a)

Moment of inertia of the cylinder is given as

$I = 1.21 \times 10^{-4} kg m^2$

Part B)

Height of the cylinder is of no use here to calculate the inertia

Part C)

Since we don't know about the viscosity data of the soup inside the cylinder so we can't say directly about the moment of inertia of the cylinder as $I = 1/2 mR^2$

Explanation:

As we know that the inclined plane is of length L = 3 m

and its inclination is given as 25 degree

so we know that acceleration of center of mass of the cylinder is constant so we will have

$v_f^2 = v_i^2 + 2 a L$

so we have

$v_f^2 = 0 + 2a(3)$

now we know that

$v_{avg} = \frac{L}{t} = \frac{v_f + v_i}{2}$

$\frac{3}{1.50} = \frac{v_f + 0}{2}$

$v_f = 4 m/s$

Now we have know that final speed of the cylinder due to pure rolling is given as

$v_f = \sqrt{\frac{2gH}{1 + \frac{I}{mR^2}}}$

$4 = \sqrt{\frac{2(9.81)(3 sin25)}{1 + \frac{I}{0.215(0.0319)^2}}}$

$I = 1.21 \times 10^[-4} kg m^2$

Part B)

Height of the cylinder is of no use here to calculate the inertia

Part C)

Since we don't know about the viscosity data of the soup inside the cylinder so we can't say directly about the moment of inertia of the cylinder as $I = 1/2 mR^2$

8 0

3 years ago

A passenger railroad car has a total of 8 wheels. Springs on each wheel compress--slightly--when the car is loaded. Ratings for

deff fn [24]

Answer:

Explanation:

mg = kx

x = mg/k

x = 30(80)(9.8)/2.8e7 = 0.00084 m ≈ 1 mm

5 0

3 years ago

3. There is a thin layer of water between the blade and the ice. Suggest how this affects friction and helps the skater? . ​

3. There is a thin layer of water between the blade and the ice. Suggest how this affects friction and helps the skater? .