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olganol [36]
3 years ago
14

Y = 2x^2

Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer:

y = 2x^2 is a parabola opening up with it's vertex at (0,0)... y=3x^2 -4 is also a parabola opening up, but it is 'thinner' in that it rises in y faster and it's vertex is at (0,-4)

Step-by-step explanation:

all equations of the type y = ax^2 + b are parabolas centered on the y-axis, soo the vertex is always on (0,b)

If a is positive then the parabola opens up,

the bigger a is, the 'thinner' the graph is, i.e. the faster the graph rises

the value of b determines the location of the vertex, if b is added, then the vertex rises over the x-axis, if b is subtracted then the vertex is below the x-axis

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artcher [175]

Answer:

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6 0
3 years ago
Write an equation and solve. Round to the nearest hundredth where necessary. What percent of 24 is 30?
garri49 [273]
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pochemuha

Answer:

Step-by-step explanation:

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3 years ago
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7 0
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schepotkina [342]

Answer:

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Step-by-step explanation:

There is no data in the image provided. To better help you, I'm assuming we have an arbitrary value of  

BC=6\sqrt{2}

and the triangle B0C is right

<u>Relations in the Circle</u>

The diameter (D) is twice the radius (r) and the radius is the distance measured from the center of the circle to any point of the circumference.  

Since the triangle B0C has a right angle, BD is the hypotenuse and 0B=0C=r

Applying Pythagoras's theorem:

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3 years ago
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