Answer:
n is equal to 26
Step-by-step explanation:
Equation: n+ n + (n+2) +(n+2) = 108
so: 2n + 2(n+2) = 108
2n + 2n + 4 = 108
4n + 4 = 108
4n = 108 - 4
4n = 104
n = 104/4
n = 26
Answer:
7 horses and 8 chickens
Step-by-step explanation:
To solve this, first you would need to list out all of the available ratios. Then, find out how many legs are in each option.:
14 horses and 1 chicken = 58 legs
13 horses and 2 chickens = 56 legs
12 horses and 3 chickens = etc.
11 horses and 4 chickens
10 horses and 5 chickens
9 horses and 6 chickens
8 horses and 7 chickens
7 horses and 8 chickens = 44 legs!
6 horses and 9 chickens
5 horses and 10 chickens
4 horses and 11 chickens
3 horses and 12 chickens
2 horses and 13 chickens
1 horses and 14 chickens
Answer:
f(x) = (3x - 7)/5
f^-1(x) = (5y + 7)/3
The DOMAIN is the set of all possible numbers that you can put in for the independent variable and get an answer. If you had g(x) = 1/x, you could NOT put in 0 for x and get an answer because 1/0 is undefined. So the domain is all numbers but 0.
The RANGE is the set of numbers you will get for the dependent variable. If you had g(x) = 1/x, you could NOT get 0 for g(x), no matter what you put in for x. So the range is all numbers but 0.
In both your functions the domain and the range equal all possible numbers. Or all real numbers.
Step-by-step explanation:
Another way to write the answers is:
D = {x | x = R} and R = {f(x) | f(x) = R} where
D = domain, R = range, { } means set, | is such that.
Answer: "greater than" for each of the 4 dropdown menus
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Explanation:
Divide each value in the table by 40
You should get:
- Horse = 15/40 = 0.375
- Cow = 12/40 = 0.300
- Sheep = 14/40 = 0.350
- Pig = 19/40 = 0.475
Those decimal results are the experimental (ie empirical) probabilities. Theoretically, we should get 1/4 = 0.250 for each sticker type assuming each sticker is likely to be chosen. As you can see, each decimal value shown above is larger than the theoretical target of 0.250, so each answer is "greater than"
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Here's another way to see why this is:
If we had 40 stickers total, and each animal has the same number of stickers, then we should have 40/4 = 10 stickers per animal type. But the table shows each frequency is above 10. So that must directly mean the empirical probability of picking any animal is greater than the theoretical probability.
