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3 years ago

7

Suppose (DE) = 103 ft. Calculate the distance of (AB) to the nearest tenth of a foot. Show your work. Don’t forget to label your

answer.

1 answer:

GarryVolchara [31]3 years ago

6 0

Here u can use photomath or wolframealpa they will solfve it for u

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Sin(60-theta)sin(60+theta)

ehidna [41]

Step-by-step explanation:

$\sin(60 - \theta) \sin(60 + \theta) \\ = \{ \sin(60) \cos( \theta) - \sin( \theta) \cos(60) \} \{ \sin(60) \cos( \theta) + \cos(60) \sin( \theta) \} \\ = \{ \frac{ \sqrt{3} }{2} \cos( \theta) - \frac{1}{2} \sin( \theta) \} \{ \frac{ \sqrt{3} }{2} \cos( \theta) + \frac{1}{2} \sin( \theta) \} \\ \\$

from difference of two squares:

${ \boxed{(a - b)(a + b) = ( {a}^{2} - {b}^{2} ) }}$

therefore:

$= \{ {( \frac{ \sqrt{3} }{2}) }^{2} { \cos }^{2} \theta \} - \{ {( \frac{ \sqrt{3} }{2} )}^{2} { \sin }^{2} \theta \} \\ \\ = \frac{3}{4} { \cos }^{2} \theta - \frac{3}{4} { \sin}^{2} \theta$

factorise out ¾ :

$= \frac{3}{4} ( { \cos }^{2} \theta - { \sin}^{2} \theta) \\ \\ = { \boxed{ \frac{3}{4} \cos(2 \theta) }}$

3 0

3 years ago

Read 2 more answers

Somebody please help me

Mazyrski [523]

Plan A: 30 + 0.01m
Plan B: 20 + 0.05m
in order for 2 plans cost the same, both need to be equal
so should be

20 + 0.05m = 30 + 0.01m

answer is D. last one
20 + 0.05m = 30 + 0.01m

8 0

3 years ago

Sydney borrowed $5500 from the bank to pay for her first semester of college. The loan has a simple interest rate of 6% for the

sergij07 [2.7K]

Answer:

$330

Step-by-step explanation:

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4 years ago

two friends are trying to get the best deal on a streaming service for movies.john choose to sign up with soupstream streaming s

dsp73

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Pls complete the question

Step-by-step explanation:

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3 years ago

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Solve this equation 4y-y+11=38

nordsb [41]

Answer:

y= 9

Step-by-step explanation:

4y-y+11=38

3y+11=38

3y= 38-11

3y= 27

y= 27/3

y=9

hope it helps ,pls mark me as brainliest

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3 years ago