Problem 1
Answer: C) No solution
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Explanation:
We have z = -4 and 4z = -4 at the same time. Solving 4z = -4 leads to z = -1
So in effect we have z = -4 and z = -1 at the same time, but this is a contradiction. A variable can only hold one number at a time.
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Problem 2
Answer: C) Infinitely many solutions
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Explanation:
The two equations are equivalent. You can prove as such by isolating 2y in the first equation.
5x = 8-2y
5x+2y = 8
2y = 8-5x
2y = -5x+8
-5x+8 = 2y
This shows the first equation is equivalent to the second, and vice versa. They both graph the same line. Any point along the line is a solution. So that's why there are infinitely many of them.
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Problem 3
Answer: Choice A) 
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Explanation:
The range is the set of the possible y values. We're concerned with every y coordinate of each (x,y) solution. So we only focus on the shaded region.
The dashed line means we exclude the boundary. It's an electric fence we cannot touch. So y > -6 or -6 < y describes part of the range
The other part is
since y = 3 is the when the highest point occurs.
So writing
describes all possible y values of each (x,y) solution in the shaded region.
Answer:
(8y+8)²+(4x²+16)=0
Step-by-step explanation:
Given:
(64y²)+(4x²)+128y+16x+64=0
Find:
Equation into the appropriate form
Computation:
(64y²)+(4x²)+128y+16x+64=0
(8y)²+(2x)²+128y+16x+64=0
(8y)²+(2x)²+2(8y)(8)+2(2x)(4) + 8²=0
(8y+8)²+(4x²+16)=0
Answer:
x=2y-9
Step-by-step explanation:
(4x³+ 13x − 7) − (6x²<span>+ 9x + 2)
Remember that if they don't have the same exponents/bases (x</span>²,x³, etc.), then they cannot be grouped together.
This means that 4x³ and 6x² will be left alone because there are no other x² or x³ in the expression.
So first thing you do is distribute. Don't forget about that - in front of the second parentheses.
(4x³+ 13x − 7) − (6x²+ 9x + 2)
(4x³ + 13x − 7) + (−6x² - 9x - 2)
4x³ - 6x² + (13x - 7) + (-9x - 2)
4x³ - 6x² + 4x (- 7) + (- 2)
4x³ - 6x² + 4x - 9
So the answer is:
C. <span>4x3− 6x2+ 4x − 9</span>