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4 years ago

Write an algebraic expression equivalent to 9x + 20 using only the commutative property of addition.

Mathematics

1 answer:

shusha [124]4 years ago

8 0

20+9x
The commutative property allows us to switch the numbers around and get the same answer

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The volume of a box without a lid is given by the formula v = 4x(10-x)^2, where x is a length in inches and v is the volume in c

Aloiza [94]

The volume of the box without the lid is 500 cubic inches.

<h3>What is volume?</h3>

The capacity of an object is measured by its volume. For instance, a cup's capacity is stated to be 100 ml if it can hold 100 ml of water in its brim.

Another way to think of volume is as the amount of space a three-dimensional object takes up.

Calculation for the volume of the box-

The volume of a box without a lid is given by the formula v = 4x(10-x)².

Where,

'x' is a length in inches, and

'v' is the volume in cubic inches.

The volume when x = 5 inches.

Substitute the value of 'x' in the formula of volume;

v = 4×5(10-5)²

= 20×5²

v = 500

Therefore, the volume of a box without a lid is 500 cubic inches.

To know more about the volume of a cardboard shoe box, here

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8 0

2 years ago

Are 35:40 and 21:24 equivalent?

andrew-mc [135]

Answer:

yes

Step-by-step explanation:

35:40=0.875

21:24=0.875

3 0

3 years ago

Read 2 more answers

Picture of raadius is 10 cm

ss7ja [257]

Step-by-step explanation:

And,what is the question so that i can help u??

6 0

3 years ago

Which of the following ordered pairs is a solution to the inequality y>−2x+7?

NNADVOKAT [17]

Answer: x>-1/2y+7/2

Step-by-step explanation:

6 0

3 years ago

A piece of cardboard has the dimensions (x + 15) inches by (x) inches with the area of 60 in 2 . Write the quadratic equation th

pochemuha

Answer:

$x^2 + 15x - 60 = 0$

The actual dimension is 18.28 by 3.28

Step-by-step explanation:

Given

Dimension:

$(x + 15)\ by\ x$

$Area = 60in^2$

Required

Determine the quadratic equation and get the possible values of x

Solving (a): Quadratic Equation.

The cardboard is rectangular in shape.

Hence, Area is calculated as thus:

$Area = Length * Width$

$60= (x + 15) * x$

Open Bracket

$60= x^2 + 15x$

Subtract 60 from both sides

$x^2 + 15x - 60 = 0$

<em>Hence, the above represents the quadratic equation</em>

Solving (b): The actual dimension

First, we need to solve for x

This can be solved using quadratic formula:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where

$a = 1$

$b = 15$

$c = -60$

So:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-15 \± \sqrt{15^2 - 4*1*-60}}{2*1}$

$x = \frac{-15 \± \sqrt{225 + 240}}{2}$

$x = \frac{-15 \± \sqrt{465}}{2}$

$x = \frac{-15 \± \21.56}{2}$

Split:

$x = \frac{-15 + 21.56}{2}$ or $x = \frac{-15 - 21.56}{2}$

$x = \frac{6.56}{2}$ or $x = \frac{-36.36}{2}$

$x = 3.28$ or $x = -18.18$

But length can't be negative;

So:

$x = 3.28$

The actual dimensions: $(x + 15)\ by\ x$ is

$Length =3.28 +15$

$Length =18.28$

$Width = x$

$Width =3.28$

<em>The actual dimension is 18.28 by 3.28</em>

3 0

3 years ago