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2 years ago

My rule is: take a number, add 15, and then subtract 9. Write down the rule.

Mathematics

1 answer:

Ksivusya [100]2 years ago

5 0

N + 15 -9
= n + 6

Is that what you’re looking for?

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Please help me on this question.

scoundrel [369]

Answer:

$f(1)=-48(-\frac{1}{4} )$

$= 12$

$f(n)=f(n-1)\:. (-\frac{1}{4} )$

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4 0

2 years ago

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What is the length of DE?

miskamm [114]

Answer:

Step-by-step explanation:

If two chords intersect in a circle, the product of the lengths of the segments of one chord equal the product of the segments of the other.

AC *CB = CD CE

4 * (10-4) = CD * 8

4 * 6 = 8 *CD

24 = 8 CD

Divide each side by 8

24/8 = CD

3 = CD

We want the length DE

DE = CD + CE

= 3 + 8

DE = 11

5 0

2 years ago

What is the solution of 2y + 3x - 6y ÷ 3x?

pentagon [3]

Answer:

=−2xy+3x+2y

Step-by-step explanation:

this is what i get in calculating

3 0

2 years ago

Evaluate the surface integral. s y ds, s is the helicoid with vector equation r(u, v) = u cos(v), u sin(v), v , 0 ≤ u ≤ 6, 0 ≤ v

Juliette [100K]

Compute the surface element:

$\mathrm dS=\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv$

$\vec r(u,v)=(u\cos v,u\sin v,v)\implies\begin{cases}\vec r_u=(\cos v,\sin v,0)\\\vec r_v=(-u\sin v,u\cos v,1)\end{cases}$

$\|\vec r_u\times\vec r_v\|=\sqrt{\sin^2v+(-\cos v)^2+u^2}=\sqrt{1+u^2}$

So the integral is

$\displaystyle\iint_Sy\,\mathrm dS=\int_0^\pi\int_0^6u\sin v\sqrt{1+u^2}\,\mathrm du\,\mathrm dv$

$=\displaystyle\left(\int_0^\pi\sin v\,\mathrm dv\right)\left(\int_0^6u\sqrt{1+u^2}\,\mathrm du\right)$

$=\dfrac23(37^{3/2}-1)$

4 0

2 years ago

What is 5 1/8 = ?/? please answer ty

beks73 [17]

Answer:

the awnser is in fraction form

$\frac{41}{8}$

3 0

2 years ago