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Viktor [21]
3 years ago
7

Faye’s bank charges her a $2.25 service fee every time she uses an out-of-network ATM. If Faye uses an out-of-network ATM twice

a week, how much money does she pay in service fees every year?
Mathematics
1 answer:
Mars2501 [29]3 years ago
4 0

Answer: the amount of money that she pays in service fees yearly is $234

Step-by-step explanation:

The number of times that Faye uses an out of network ATM is twice in a week. Assuming that the total number of weeks in a year is 52 weeks in a year. It means that the number of times that she uses an out of network ATM in a year is 62 × 2 = 104 times.

Faye’s bank charges her a $2.25 service fee every time she uses an out-of-network ATM. It means that the total cost for using an Faye’s bank charges her a $2.25 service fee every time she uses an out-of-network ATM for 104 times will be

2.25 × 104 = $234

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tresset_1 [31]

Answer:

10%

Step-by-step explanation:

10% of 36 is 3.6   If you add 3.6 to 36 you get 39.6      hope you did good

4 0
3 years ago
A triangular window pane has a base of 30 inches and a height of 24 inches.What is the area of the window pane?
densk [106]

54 or it 180 i got 54 by adding 30 and 24in and got 180 by multiplying

8 0
3 years ago
Read 2 more answers
If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

4 0
1 year ago
Py+7=6y+q<br> what is the answer for this question (linear equations with unknown coefficients)?
Temka [501]
Assuming your solving for y:
py+7=6y+q
-6y -7 -6y -7
(p-6)y = q-7
divide both sides by p-6
y=(q-7)/(p-6)
3 0
3 years ago
Read 2 more answers
What is the surface area of a rectangular prism?<br><br>length : 3<br>width : 3<br>height = 5
elixir [45]
Since it is a rectangular prism, the front and back are the same. the sides are the same and the top and bottom are the same. You would find the area of the front and back first. Since they both have the same measurements, you can find the area of one of the faces and multiply by 2.
A=BH
A= 3x5
A=15
15x2=30
So the front and back's area is 30. Now you find the area of both sides. They are both rectangle so the formula is A=BH.
A=BH
A=3x5
A=15
15x2=30
Now you find the area of the top and bottom. It is also a rectangle so you will use the same formula.
A=BH
A=3x3
A=9
9x2=18
Finally, you add all these measurements together adn that is the surface area. 
This surface area of this rectangle prism is 78.
4 0
3 years ago
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