Hey. Let me help you on this one.
Let's break this problem down so it's easier for us to comprehend it.
There are 850 students in the school, and the amount of female students equals to the amount of male students + sixty additional females.
Amount of students in school = 850 students
Male students =

Female students =

Let's form an equation so we can work with what we have.

Subtract 60 from both sides.

Simplify

Divide both sides by 2.

Answer: There are 395 male students, and 455 female students.
Answer:
The measure of the angles are 40 degrees and 50 degrees
Step-by-step explanation:
Let
x ----> the measure of one angle in degrees
y ----> the measure of the complementary angle in degrees
we know that
If two angles are complementary, then their sum is equal to 90 degrees
so
----> equation A
we have that
----> equation B
Substitute equation B in equation A and solve for y

Find the value of x

therefore
The measure of the angles are 40 degrees and 50 degrees
The answer to 25. is A
and
to 26. is C (I'm not sure on this one but i think this is the answer)
2 1/24
Rewriting our equation with parts separated
2/3+1+3/8
Solving the fraction parts
2/3+3/8=?
Find the LCD of 2/3 and 3/8 and rewrite to solve with the equivalent fractions.
LCD = 24
16/24+9/24=25/24
Simplifying the fraction part, 25/24,
25/24=1 1/24
Combining the whole and fraction parts
1+1+1/24=2 1/24