Use the Rythagorean Theorem to find the length of
1 answer:
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The width of the rectangle is unit
Step-by-step explanation:
The given is:
- A rectangles width is 4 less than its area
- Its length is 19 units
We need to find the width of the rectangle
Assume that the width of the rectangle is x units
∵ The area of the rectangle = length × width
∵ The width of the rectangle = x units
∵ The length of the rectangle = 19 units
∴ The area of the square = 19 × x = 19 x units²
∵ The width of the rectangle is 4 less than its area
- That means subtract 4 from the area to find the width
∴ x = 19 x - 4
- Subtract 19 x from both sides
∴ -18 x = -4
- Divide both sides by -18
∴ x =
- Reduce the fraction by dividing up and down by -2
∴ x =
The width of the rectangle is unit
Learn more:
You can learn more about the rectangles in brainly.com/question/12919591
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Define
g = 9.8 32.2 ft/s², the acceleration due to gravity.
Refer to the diagram shown below.
The initial height at 123 feet above ground is the reference position. Therefore the ground is at a height of - 123 ft, measured upward.
Because the initial upward velocity is - 11 ft/s, the height at time t seconds is
h(t) = -11t - (1/2)gt²
or
h(t) = -11t - 16.1t²
When the ball hits the ground, h = -123.
Therefore
-11t - 16.1t² = -123
11t + 16.1t² = 123
16.1t² + 11t - 123 = 0
t² + 0.6832t - 7.64 = 0
Solve with the quadratic formula.
t = (1/2) [-0.6832 +/- √(0.4668 + 30.56) ] = 2.4435 or -3.1267 s
Reject the negative answer.
The ball strikes the ground after 2.44 seconds.
Answer: 2.44 s
g = 9.8 32.2 ft/s², the acceleration due to gravity.
Refer to the diagram shown below.
The initial height at 123 feet above ground is the reference position. Therefore the ground is at a height of - 123 ft, measured upward.
Because the initial upward velocity is - 11 ft/s, the height at time t seconds is
h(t) = -11t - (1/2)gt²
or
h(t) = -11t - 16.1t²
When the ball hits the ground, h = -123.
Therefore
-11t - 16.1t² = -123
11t + 16.1t² = 123
16.1t² + 11t - 123 = 0
t² + 0.6832t - 7.64 = 0
Solve with the quadratic formula.
t = (1/2) [-0.6832 +/- √(0.4668 + 30.56) ] = 2.4435 or -3.1267 s
Reject the negative answer.
The ball strikes the ground after 2.44 seconds.
Answer: 2.44 s