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Jet001 [13]
3 years ago
11

Factor the expression below so it is in simplest form.

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Answer:

add my sc = bmic ava, no spaces

or add my discord = XoXo_ava

Step-by-step explanation:

urmom gfghdfhghhgfdghjgfdsghjkhgfd fuhgjk rfujgyhbm

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19. Tom has 30 coins with a value of $3.30. If they are all nickels and quarters, how many of each kind of coin does
vova2212 [387]

Answer:

n = nickels, q = quarters

Equation 1: n+q=30

Equation 2: 0.05n+0.25q = 3.30

Step-by-step explanation:

From equation 1, n = 30-q

Substitute in Equation 2:

0.05(30-q) + 0.25q = 3.30

1.5 - 0.05q + 0.25q = 3.30

0.2q = 1.8

q = 9

Substitute in new equation:

n = 30-9

n = 21

It is important to note a nickel is worth 5 cents and a quarter is 25 cents. This helps us build the equations.

4 0
3 years ago
If A, B, and C are mutually exclusive events with P(A) = 0.2, P(B) = 0.3, and P(C) = 0.4, determine the following probabilities:
fiasKO [112]

a. The events are mutually exclusive, so

P(A\cup B\cup C)=P(A)+P(B)+P(C)=\boxed{0.9}

b. For the same reason,

P(A\cap B\cap C)=\boxed0

Another way to see this is to use the result from part (a), and the inclusion/exclusion principle:

P(A\cap B\cap C)=P(A)+P(B)+P(C)-P(A\cup B\cup C)

and the right side reduces to 0.

c. Same as (b),

P(A\cap B)=\boxed0

d. Same as (b),

P((A\cup B)\cap C)=\boxed0

We can also use the distributivity rule for unions and intersections to write

P((A\cup B)\cap C)=P((A\cap C)\cup(B\cap C))=P(A\cap C)+P(B\cap C)=0

e. If the A' is the complement of A, then by DeMorgan's law,

P(A'\cap B'\cap C')=P(A\cup B\cup C)'=1-P(A\cup B\cup C)=\boxed{0.1}

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3 years ago
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1 st 2nd and 4th are NOT parallelograms.
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Picture is to blurry fix the pic and I will answer it if I can
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Is 3.61 less than 3.87
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Step-by-step explanation:

yes because 61 is less than 87

5 0
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