What is the perimeter of a rectangle whose length is M cm and width is 2 cm
1 answer:
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Answer:
- D. A translation 1 unit to the right followed by a 270-degree counterclockwise rotation about the origin
Step-by-step explanation:
<em>See the picture for better visual</em>
Take segments ST and S'T'. If we extend them they will intersect at right angle.
It is the indication that the rotation is 90° or 270° but not 180°, when the corresponding segments come parallel.
The QRST is in the quadrant IV and Q'R'S'T' is in the quadrant III, which mean the rotation is 90° clockwise or 270° counterclockwise.
<u>This rotation rule is:</u>
- (x, y) → (y, -x)
We also see the points S and T have x-coordinate of 5 but their images have y-coordinates of -6. It means the translation to the right by 1 unit was the step before rotation.
<u>We now can conclude the correct choice is D:</u>
- A translation 1 unit to the right followed by a 270-degree counterclockwise rotation about the origin
Answer:
look at the photo
Step-by-step explanation:
Since the inequality is already written in y=mx+b, you can easily graph the line. +3 is the y intercept, so one point would be (0,3). -2 resembles the slope, so diagonally to the left, you would go up 2 and across 1. Also, since the sign is "<" you would graph with a dotted line. Then to know which side to shade, I always use the coordinate (0,0). I plug in 0 for both x and y to see if (0,0) satisfies the inequality. In this case it does, so you would shade on the side where (0,0) is located.
