Answer:
Point N(3,0) is equidistant from A and B.
Step-by-step explanation:
In order to check whether the point is equidistant from A and B, it is required to measure the distance of A and B from each point. The formula for distance is:
d= √((x_2-x_(1))^2+(y_2-y_(1))^2 )
For J
AJ= √((-4-0)^2+(-5+4)^2 )
=√((-4)^2+(-1)^2 )
= √(16+1)
= √17 units
BJ=√((-4+2)^2+(-5-0)^2 )
=√((-2)^2+(-5)^2 )
= √(4+25)
= √29 units
Point J is not equidistant from A and B.
For K
AK= √((-3-0)^2+(0+4)^2 )
=√((-3)^2+(4)^2 )
= √(9+16)
= √25 units
=5
BK=√((-3+2)^2+(0-0)^2 )
=√((-1)^2+(0)^2 )
= √(1+0)
= √1
=1 unit
Point K is not equidistant from A and B.
For M
AM= √((0-0)^2+(0+4)^2 )
=√((0)^2+(4)^2 )
= √(0+16)
= √16
=4 units
BM=√((0+2)^2+(0-0)^2 )
=√((2)^2+(0)^2 )
= √(4+0)
= √4
=2 units
Point M is not equidistant from A and B.
For N
AN= √((3-0)^2+(0+4)^2 )
=√((3)^2+(4)^2 )
= √(9+16)
= √25
=5 units
BN=√((3+2)^2+(0-0)^2 )
=√((5)^2+(0)^2 )
= √(25+0)
= √25
=5 units
As point N's distance is equal from A and B, Point N is equidistant from A and B.
.
You will need to find the cube root of 125......which is 5
Answer:
The answer is: The adult ticket costs $15 and the child ticket costs $10.
Step-by-step explanation:
Let a = the dollar amount of adult tickets and c = the dollar amount for child tickets. The child ticket cost $5 less than the adult ticket. Then:
c = a - 5
The number of adult tickets times the adult cost plus the number of child tickets times the cost for child tickets is equal to the total dollar amount. Set up the equation:
8a + 2c = $140
Substitute:
8a + 2(a-5) = 140
8a + 2a - 10 = 140
10a = 150
a = 150 / 10 = 15, so the adult ticket is $15
Solve for c:
c = a - 5
c = 15 - 5 = 10, so the child ticket is $10
Proof:
8a + 2c = 140
8(15) + 2(10) = 140
120 + 20 = 140
140 =140
Answer:
4x+36
Step-by-step explanation:
All you have to do is multiply the 4 by the numbers inside the parentheses.
4 times x is 4x
4 times 9 is 36
You can't find the answer since you don't know what x is.
I hope this helps, and have a great day! :)
