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Vlad1618 [11]
2 years ago
13

Que pasa si un objeto imparable choca con uno inabobible​

Mathematics
2 answers:
natima [27]2 years ago
8 0

Step-by-step explanation:

¿Qué pasaría si una fuerza imparable chocara contra un objeto inamovible? Las respuestas comunes a esta paradoja recurren a la lógica y a la semántica.

Lógica: Si existe una cosa tal como una fuerza imparable, entonces no puede existir un objeto inamovible y viceversa. Es lógicamente imposible la existencia de los objetos (una fuerza imparable y un objeto inamovible) en un mismo universo al mismo tiempo.

Semántica: Si existe una cosa tal como una fuerza imparable, entonces hablar de un objeto inamovible no tendría sentido en ese contexto y viceversa, con lo cual el asunto vendría a ser algo así como preguntar, por ejemplo, por un triángulo de cuatro lados.

kobusy [5.1K]2 years ago
7 0

English Answer: No object can resist an irresistible force. No force can move an immovable object. So if an immovable object meets an irresistible force it will move and not move.English:

Spanish Answer: Ningún objeto puede resistir una fuerza irresistible. Ninguna fuerza puede mover un objeto inamovible. Entonces, si un objeto inamovible se encuentra con una fuerza irresistible, se moverá y no se moverá.

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Which equation represents the line shown on the graph in the picture
natima [27]

Answer:

either the second one or the fourth one. good luck

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please help show work too please thank you
Black_prince [1.1K]
(3x-9) +(x+19)+x=180
5x+10=180
-10=-10
5x=170
5 = 5
x=34

2x+(2x+10)+x=180
5x+10=180
-10=-10
5x=170
5 = 5
x=34

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photoshop1234 [79]

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8 0
3 years ago
The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

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7 0
3 years ago
What is the value of x in the equation 3x-5=-18?<br> -56<br> 52<br> 56
anygoal [31]
I’ll teach you how to solve 3x-5=-18
—————————————-
3x-5=-18
Move constant to the right-hand side and change its sign:
3x=-18+5
Calculate the sum:
3x=-13
Divide both sides of the equation by 3:
X=-13/3
Your Answer Is x=-13/3
Plz mark me as brainliest if this helped :)
8 0
3 years ago
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