x^(2/5) + x^(1/5) + 1 = 3
subtract 3 from each side
x^(2/5) + x^(1/5) -2=0
let m = x^1/5
m^2 +m -2 =0
(m - 1) (m + 2) = 0
using the zero product property
m=1 m=-2
replace m = x^1/5
x^1/5 =1 and x^1/5 = -2
take everything to the 5th powr
x^ 1/5 ^ 5 = 1^5 and x^ 1/5 ^ 5 = -2 ^ 5
x = 1 and x = -32
Choice C
C. -32, 1
The answers are 1) B 2) B 3) A
Answer:
60 combinations
Step-by-step explanation:
3 × 4 × 5 = 60
Hope i helped!
Answer:
0.19
0.13
0.11
because that is how 19, 13, and 11 percent are represented in decimal form
(4*2)-(2*-3)+(5*5)= 8-6+25= 27
