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3 years ago

If three bakers can prepare 15

Mathematics

1 answer:

Molodets [167]3 years ago

3 0

Answer:

45 cakes/3 hours

Step-by-step explanation:

15 cakes/1 hour = x cakes = 3 hours (multiply by 3)

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Khan uses 78 feet of fence to make a rectangular pen for his pet rabbit. The length of the pen is 25 feet. What is the width of

Anna35 [415]

The width of the rectangular pen is equal to 14 feet.

7 0

2 years ago

Cell phone companies estimate that the total number of text messages (t) since the beginning of the month can be modeled by t=40

GalinKa [24]

The desired number is the difference between the number of messages sent by the 16th day and the number sent by the 9th day:

... n = t(16) - t(9)

... n = (40×√16) - (40×√9)

... n = 40×(4 - 3) = 40

40 text messages were sent between the ninth and sixteenth day of the month.

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3 years ago

6 points are placed on the line a , 4 points are placed on the line b . How many triangles is it possible to form such that thei

BaLLatris [955]

Answer:

Step-by-step explanation:

Using side b as the base, 4 points makes 3 bases (the space in between). With three bases, you can have 3 bases of 1 segment, 2 bases of 2 segments, and 1 base of 3 segments. This equals 6 bases. Each of these can connect to a point on line a. 6x6=36

Using side a as the base, 6 points makes 5 bases. With 5 bases, you can have 5 bases of 1 segment, 4 bases of 2 segments, 3 bases of 3 segments, 2 bases of 4 segments, and 1 base of 5 segments. This equals 15 bases. Each of these can connect to a point on line b. 15x4=60

36+60=96

5 0

3 years ago

Read 2 more answers

Four different paints are advertised as having the same drying time. To check the manufacturer's claims, five samples were teste

iogann1982 [59]

Answer:

Explained below.

Step-by-step explanation:

The data provided is for the dying time of four different types of paint.

One-way ANOVA can be used to determine whether all the four paints have the same drying time.

Use Excel to perform the one-way ANOVA.

Go to Data → Data Analysis → Anova: Single Factor

A dialog box will open.

Select the data.

Select "Grouping" as Columns.

Press OK.

The output is attached below.

The required values are as follows:

(1)

Sum of Squares of Treatment (Between Subjects):

SST = 330

(2)

Sum of Squares of Error (Within Subjects):

SSE = 692

(3)

Mean Squares Treatment (Between Subjects):

MST = 110

(4)

Mean Squares Error (Within Subjects):

MSE = 43.25

6 0

3 years ago

Paul says that (3.14 X 10^5) + (2.53 X 10^4) = 5.67 X 10^5. Is Paul correct? Explain.

Marizza181 [45]

He is false the equation should be as follows

3 0

2 years ago