Answer:
a) 94 degrees lower
b) -17 degrees
Step-by-step explanation:
you should draw a number line to visualize what i'm saying..
basically any number that has a greater value but is negative is obviously lower than a smaller negative value
for example: take -563 that is a lot less than -31 because its farther down the number line
okay to find the answer to question a) you need to obviously find the difference between -29 and 65 to do that you need to count the space in between -29 and 65 on a number line.
There's actually a much easier method just use your common sense and some math: so you can say the distance from 0 to 65 is … 65 and the distance from -29 to 0 is 29 so to find the total distance you add them up and you get your answer! (94)
for b) its even easier you just take the number -29 and add 12 from it to get closer to 0 so to do that you need to subtract 12 to get a smaller number but bigger value on the number line (if you draw this one out it will make sense). And the answer is... -17! I hope this made sense :)
Answer:
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Answer:
9
Step-by-step explanation:
Answer:
The rate of change of the volume 
when the height is 9 centimeters and the radius is 6 centimeters is 
Step-by-step explanation:
This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.
From the information given we know:
- The volume of a cone of radius r and height h is given by
We want to find the rate of change of the volume when the height is 9 centimeters and the radius is 6 centimeters.
Applying implicit differentiation to the formula of the volume of a cone we get
![\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%20%5Br%5E2%5Cfrac%7Bdh%7D%7Bdt%7D%2B2rh%5Cfrac%7Bdr%7D%7Bdt%7D%20%5D)
Substituting the values we know into the above formula:
![\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%20%5B%286%29%5E2%5Cfrac%7B1%7D%7B2%7D%2B2%286%29%289%29%5Cfrac%7B1%7D%7B2%7D%20%5D%5C%5C%5C%5C%5Cfrac%7BdV%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%5B18%2B54%5D%5C%5C%5C%5C%5Cfrac%7BdV%7D%7Bdt%7D%3D%5Cfrac%7B72%5Cpi%7D%7B3%7D%3D24%5Cpi%20%5C%3A%5Cfrac%7Bcm%5E3%7D%7Bs%7D)
Answer:
yes I believe it is a function
