Answer:
Step-by-step explanation:
Answer is C
We need to find oblique asymtotes of f(x).
Oblique asymtotes form when degree of numerator is greater than denominator.
First we find the degree of numerator and denominator for f(x)
Degree of f(x) at numerator = 2
Degree of f(x) at denominator = 1
So, one oblique asymtote form.
First we divide by
Quoetient of the above division would be oblique asymtote.
First we find the degree of numerator and denominator for f(x)
Degree of f(x) at numerator = 2
Degree of f(x) at denominator = 1
So, one oblique asymtote form.
Presuming the question is "Which sum is closest to 1".
First, you need to either convert all the fractions to decimals or all the decimals to fractions, then add each pair.
0.4 + 1/2 = 0.9
7/8 + 1/4 = 1.125
4/5 + 2/3 = 1.466666...
The first one is different from 1 by 0.1. The second is different by 0.125. The third is different by 0.46666.... Therefore, the closest sum is the first, or 0.4 + 1/2
0.4 + 1/2
Answer:
x = 5
Step-by-step explanation:
Given
x = 
( square both sides )
x² = 3x + 10 ( subtract 3x + 10 from both sides )
x² - 3x - 10 = 0 ← in standard form
(x - 5)(x + 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 5 = 0 ⇒ x = 5
x + 2 = 0 ⇒ x = - 2
As a check
Substitute these values into the equation and if both sides are equal then they are solutions.
x = 5
right side = 
= 
= 5 = left side ← solution
x = - 2
right side = 
= 
= 2 ≠ - 2 ← not a solution
Thus x = 5 is the solution to the equation
Answer:
x=5
Step-by-step explanation:
5x-3=22
5x-3+3=22+3
5x=25
25/5=5
x=5
