I believe you just add all the numbers then divide by how many were there. You would divide by 16.
36 Cards given away
Roberto has nine so that means everyone else also has nine since they're equal
Therefore
9 cards x 4 other people= 36 cards given
It is the simplest form if you are asking for improper fraction then we can do that
7 1/7
C because 9 + 5 is not 15 and because 13 + 5 is not 20
Answer:
The value of car after n years at the depreciation rate is $ 50,000
.
Step-by-step explanation:
Given as :
The cost of the car that Jill bought = $ 50,000
The depreciation rate of car value = r = 10 % a years
Let The car after n years of depreciation = $ A
Now, According to question
The cost of car after n years of depreciation = initial cost of car × ![(1 - \dfrac{\textrm rate}{100})^{\textrm time}](https://tex.z-dn.net/?f=%281%20-%20%5Cdfrac%7B%5Ctextrm%20rate%7D%7B100%7D%29%5E%7B%5Ctextrm%20time%7D)
Or, $ A = $50,000 × ![(1 - \dfrac{\textrm r}{100})^{\textrm n}](https://tex.z-dn.net/?f=%281%20-%20%5Cdfrac%7B%5Ctextrm%20r%7D%7B100%7D%29%5E%7B%5Ctextrm%20n%7D)
Or, $ A = $50,000 × ![(1 - \dfrac{\textrm 10}{100})^{\textrm n}](https://tex.z-dn.net/?f=%281%20-%20%5Cdfrac%7B%5Ctextrm%2010%7D%7B100%7D%29%5E%7B%5Ctextrm%20n%7D)
Or, $ A = $50,000 × ![(\frac{90}{100})^{n}](https://tex.z-dn.net/?f=%28%5Cfrac%7B90%7D%7B100%7D%29%5E%7Bn%7D)
I.e $ A = $50,000 × ![(0.9)^{n}](https://tex.z-dn.net/?f=%280.9%29%5E%7Bn%7D)
So, value of car after n years = $ 50,000 ![(0.9)^{n}](https://tex.z-dn.net/?f=%280.9%29%5E%7Bn%7D)
Hence The value of car after n years at the depreciation rate is $ 50,000
. Answer