All categories

3 years ago

PLZ HELP ME I BEG YOU I WILL GIVE BRAINLIEST

Mathematics

1 answer:

Stella [2.4K]3 years ago

4 0

Answer: Mean: 10, Mode 14, and so on. The third one.

Step-by-step explanation: I solved for the mean first. You just add up all the numbers then divide by how many there are. For mode, you find the most common number, or the one that repeats the most.

You might be interested in

Jody bought some scarves that cost $8

Fofino [41]

Answer:

5 scarves

Step-by-step explanation:

8x5=40

5 0

3 years ago

Read 2 more answers

Tamar rides her bike 960 feet in 2 minutes. What is her rate of speed?

Alekssandra [29.7K]

Answer:

Rate of speed = 480 feet per minutes

Step-by-step explanation:

Given:

Distance covered by bike = 960 feet

Time taken to covered distance = 2 minutes

Find:

Rate of speed = ?

Computation:

⇒ Speed = Distance / Time

⇒ Rate of speed = Distance covered by bike / Time taken to covered distance

⇒ Rate of speed = 960 / 2

⇒ Rate of speed = 480 feet per minutes

5 0

3 years ago

Hilary's Horse Hideaway is buying dirt to fill their circular training area. The training circle is 28 feet across. What is the

AnnZ [28]

Answer:

A = 615.75

cost = $107.08

Step-by-step explanation:

the training area = (28/2)^2*pi

training area = 615.75 square feet

615.75/5.75 = 107.08

$107.08

5 0

2 years ago

Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage r

monitta

Answer:

Decay

since 0.292 is less than 1

% rate of decrease

1 - 0.292 = 0.708

70.8%

4 0

3 years ago

The mass, m grams, of a radioactive substance, present at time t days after first being observed, is given by the formula m=24e^

Reika [66]

Answer:

(i) The value of m when t = 30 is 13.2

(ii) The value of t when the mass is half of its value at t=0 is 34.7

(iii) The rate of the mass when t=50 is -0.18

Step-by-step explanation:

(i) The m value when t = 30 is:

$m = 24e^{-0.02t} = 24e^{-0.02*30} = 13.2$

Then, the value of m when t = 30 is 13.2

(ii) The value of the mass when t=0 is:

$m_{0} = 24e^{-0.02t} = 24e^{-0.02*0} = 24$

Now, the value of t is:

$ln(\frac{m_{0}/2}{24}) = -0.02t$

$t = -\frac{ln(\frac{24}{2*24})}{0.02} = 34.7$

Hence, the value of t when the mass is half of its value at t=0 is 34.7

(iii) Finally, the rate at which the mass is decreasing when t=50 is:

$\frac{dm}{dt} = \frac{d}{dt}(24e^{-0.02t}) = 24(e^{-0.02t})*(-0.02) = -0.48* (e^{-0.02*50}) = -0.18$

Therefore, the rate of the mass when t=50 is -0.18.

I hope it helps you!

3 0

3 years ago