Which is the equation of a line that has a slope of 3/2 and has the point of (-10,4)
1 answer:
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Answer:
(a) median = 57
(b) Q1=50 Q3=63.5
(c)D1 = 41 D9=67
(d)P33= 51
Step-by-step explanation:
(a) The numbers are arranged in ascending order, and there are even number of calls. So the median will be the average of the middle terms.
middle terms are 55 and 59
Median =
median= 57
(b) First quarter Q1 = th
=th
= 7.5th
so the first quarter lies in the 7.5th= (7+0.5)th term
So we multiply 0.5 by the difference of the 7th and 8th term
=0.5 *0= 0
Q1 = 50+0=50
Q3=th
=th
=22.5th = (22+0.5)th term
So we multiply 0.5 by the difference of the 22th and 23rd term
= 0.5*1=0.5
Q3= 63+0.5=63.5
(c) First decile (D1) = th
=th
= 3rd term
D1= 41
D9= th
=th
=27th term
D9 = 67
(d) 33rd percentile =th
=th
= 9.9th term = (9 +0.9)th
Multiply 0.9 by the difference between the 9th and tenth term.
= 0.9*0 =0
P33 = 51
Answer:
157.14 m²
Step-by-step explanation:
Refer to attachment
Hope it helps :)
